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irakobra [83]
3 years ago
13

A rocket in the shape of acone is attached to a cylinder with the same base radius the cone has aslant height of 15m the cylinde

r has abase diameter of 12m and a height of 42m find the total surface area of the rocket
Mathematics
1 answer:
Nataliya [291]3 years ago
7 0

Answer:

the total surface area of the rocket: 1978.2  m^{2}  

Step-by-step explanation:

Given that :

  • A rocket in the shape of a cone
  • The aslant height: 15m
  • The base diameter: 12m <=.> Radius: 6m
  • The height: 42

So the surface area of a a cone with about the base area because it is attached to a cylinder:

= π*r*l = 3.14*6*15 = 282.6 m^{2}

The area of the cylinder is: 2*π*r*h+pi*r^{2} (without the top part of it)

= 2*3.14*6*42 + 3.14*6^{2}

= 1695.6 m^{2}  

At the end, the total surface area of the rocket:

1695.6 m^{2}  + 282.6 m^{2} = 1978.2  m^{2}  

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8 0
3 years ago
NEED ANSWER
grandymaker [24]

Answer:

\frac{x^{2}}{144}+\frac{y^{2}}{79.995}=1

Step-by-step explanation:

An ellipse centered a point (h,k) has the following formula:

\frac{(x-h)^{2}}{a^{2}}+\frac{(y-k)^{2}}{b^{2}}=1

The distance between foci is:

2\cdot c = \sqrt{[8-(-8)]^{2}+(0-0)^{2}}

2\cdot c = 16

c = 8

The center of the ellipse is:

C(x,y) = (-8 + 8, 0 + 0)

C(x,y) = (0,0)

The known vertex is on the horizontal axis of the ellipse. Then, the length of the semi-major axis is:

a = \sqrt{(12-0)^{2}+(0-0)^{2}}

a= 12

The length of the semi-minor axis is given by the following expression:

c =\sqrt{a^{2}-b^{2}}

b = \sqrt{a^{2}-c^{2}}

b = \sqrt{12^{2}-8^{2}}

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The equation of the ellipse is:

\frac{x^{2}}{144}+\frac{y^{2}}{79.995}=1

5 0
3 years ago
What is the value of x?
REY [17]

Answer:

The missing side has a length equal to 15\sqrt{3}

Step-by-step explanation:

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5 units^2

Step-by-step explanation:

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plugging in:

\frac{5 \times 2}{2}

\frac{10}{2}

5

4 0
3 years ago
Read 2 more answers
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