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irakobra [83]
3 years ago
13

A rocket in the shape of acone is attached to a cylinder with the same base radius the cone has aslant height of 15m the cylinde

r has abase diameter of 12m and a height of 42m find the total surface area of the rocket
Mathematics
1 answer:
Nataliya [291]3 years ago
7 0

Answer:

the total surface area of the rocket: 1978.2  m^{2}  

Step-by-step explanation:

Given that :

  • A rocket in the shape of a cone
  • The aslant height: 15m
  • The base diameter: 12m <=.> Radius: 6m
  • The height: 42

So the surface area of a a cone with about the base area because it is attached to a cylinder:

= π*r*l = 3.14*6*15 = 282.6 m^{2}

The area of the cylinder is: 2*π*r*h+pi*r^{2} (without the top part of it)

= 2*3.14*6*42 + 3.14*6^{2}

= 1695.6 m^{2}  

At the end, the total surface area of the rocket:

1695.6 m^{2}  + 282.6 m^{2} = 1978.2  m^{2}  

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