It is given that area( Δ ab c) =6 square units.
Also ab║d e
⇒b d =4 b c
I have depicted picture below.
Consider Δ cde in which points a and b are in the interior such that ab║de.
So, as you know that if in a triangle line joining two points is parallel to third side then the two sides are proportional.i.e
⇒ca/ae =cb / bd
Also, ∠ c is common.
∴Δcab is similar to Δ cde.
As we know if ratio of areas of two similar triangles is square of their corresponding sides.
=![\frac{Ar(Δcab)}{Ar(Δcde)}=[\frac{cb}{bd}]^2](https://tex.z-dn.net/?f=%5Cfrac%7BAr%28%CE%94cab%29%7D%7BAr%28%CE%94cde%29%7D%3D%5B%5Cfrac%7Bcb%7D%7Bbd%7D%5D%5E2)
⇒6/Δcde =1/4
⇒Ar (Δ cde)=6×4
Ar (Δ cde) =24 square centimeter