What is the mean of -3, 4, 8, -1, -4, -2, 0, 2, 5, 2, -3, 1
Rom4ik [11]
Answer:
3/4 or .75
Step-by-step explanation:
The mean means the average so you would add up all the numbers then divide by how many numbers there are
-3+4+8+-1+-4+-2+0+2+5+2+-3+1= 9
9/12= 3/4 or .75
depends whether or not you want it in fraction or decimal form
Answer:
The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.
Step-by-step explanation:
The area of a sphere is given by the following formula:

In which A is the area, measured in cm², and r is the radius, measured in cm.
Assume that the radius r of a sphere is expanding at a rate of 40 cm/min.
This means that 
Determine the rate of change in surface area when r = 20 cm.
This is
when
. So

Applying implicit differentiation.
We have two variables, A and r, so:



The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.
Answer:
D angle 6
Step-by-step explanation:
Corresponding angles are in the same place if the line were on top of each other. For example, ang1e 1 and angle 5, are corresponding; angle 3 and angle 7 are corresponding.
Answer:
(x,y) = (1,2)
Step-by-step explanation:
I used a graphing calculator and put both equations in to find the intersection.