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Virty [35]
4 years ago
8

$30.50 - $17.79= what Solve this problem in two diffrent ways (5th grade math)

Mathematics
2 answers:
Ksivusya [100]4 years ago
6 0

Answer: answer is 12.71

Step-by-step explanation:

I just did it like normal math subtraction with out dots an them at the end i putted dots and got answer easy-peasy

puteri [66]4 years ago
4 0
$30.50-$17.79 is $12.71. I hope that helps you :)
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5+ 1/5x=5 what is x
Alenkasestr [34]

Answer:

x = 0

Step-by-step explanation:

Solve for x:

x/5 + 5 = 5

Put each term in x/5 + 5 over the common denominator 5: x/5 + 5 = x/5 + 25/5:

x/5 + 25/5 = 5

x/5 + 25/5 = (x + 25)/5:

(x + 25)/5 = 5

Multiply both sides of (x + 25)/5 = 5 by 5:

(5 (x + 25))/5 = 5×5

(5 (x + 25))/5 = 5/5×(x + 25) = x + 25:

x + 25 = 5×5

5×5 = 25:

x + 25 = 25

Subtract 25 from both sides:

x + (25 - 25) = 25 - 25

25 - 25 = 0:

x = 25 - 25

25 - 25 = 0:

Answer:  x = 0

4 0
3 years ago
Read 2 more answers
A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
Oksanka [162]

Answer:

a) [-0.134,0.034]

b) We are uncertain

c) It will change significantly

Step-by-step explanation:

a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

Since we assume that the variances are equal, we use the pooled variance given as

s_p^2 = \frac{ (n_1 -1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2},

where n_1 = 40, n_2 = 30, s_1 = 0.16, s_2 = 0.19.

The mean difference \mu_1 - \mu_2 = 10.85 - 10.90 = -0.05.

The confidence interval is

(\mu_1 - \mu_2) \pm t_{n_1+n_2-2,\alpha/2} \sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2}} = (-0.05) \pm t_{68,0.025} \sqrt{\frac{0.03}{40} + \frac{0.03}{30}}

= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]

b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

6 0
4 years ago
Help? i really don’t understand :(((
horsena [70]

Answer:

whats the question

Step-by-step explanation:

6 0
3 years ago
There are 12 boys and 15 girls in your class for new students three boys and one girl join your class what is the ratio of the c
Finger [1]
Before the new kids the ratio of girls to boys is 15:12 because there are 15 girls and 12 boys now you can simplify by dividing 15 by 3 and 12 by 3 to get 5:4 as your simplified ratio. As far as after the new kids. Since there is 1 new girl you do 15+1 to get 16 and there are 3 new boys so you do 12+3 to get 15 now 16:15 is already in simplest form so your answer is:

Before: 15:12 simplified as 5:4
After 16:15
6 0
3 years ago
Read 2 more answers
HELP PLEASE! I'm not sure what the right answer is.
jasenka [17]
I'm really not sure.
Sorry.
3 0
3 years ago
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