Answer:
The magnitude of the magnetic field at the center of the loop is 4.578 x 10⁻⁵ T
Explanation:
Given;
number of turns of the circular loop, n = 15 turns
radius of the loop, R = 10.5 cm
current flowing in the wire, I = 0.51 A.
Magnetic flux, at the center of the loop is given as;
B = μ₀nI / 2R
Where;
B is the magnitude of the magnetic field at the center of the loop
μ₀ is constant, = 4π x 10⁻⁷ Tm/A
Substitute in the given values into the equation above and calculate B
B = ( 4π x 10⁻⁷ x 15 x 0.51) / (2 x 0.105)
B = 4.578 x 10⁻⁵ T
Therefore, the magnitude of the magnetic field at the center of the loop is 4.578 x 10⁻⁵ T
