Question

A flat, circular loop has 15 turns. The radius of the loop is 10.5 cm and the current through the wire is 0.51 A. Determine the magnitude of the magnetic field at the center of the loop (in T).

Answer 1

Answer:

The magnitude of the magnetic field at the center of the loop is 4.578 x 10⁻⁵ T

Explanation:

Given;

number of turns of the circular loop, n = 15 turns

radius of the loop, R = 10.5 cm

current flowing in the wire, I = 0.51 A.

Magnetic flux, at the center of the loop is given as;

B = μ₀nI / 2R

Where;

B is the magnitude of the magnetic field at the center of the loop

 μ₀ is constant, = 4π x 10⁻⁷ Tm/A

Substitute in the given values into the equation above and calculate B

B = ( 4π x 10⁻⁷  x 15 x 0.51) / (2 x 0.105)

B = 4.578 x 10⁻⁵ T

Therefore, the magnitude of the magnetic field at the center of the loop is 4.578 x 10⁻⁵ T