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Semenov [28]
4 years ago
8

a)Show that whennbecomes very large, the energy levels of the hydrogen atom are getting closer to energy.b)Are the rays of these

levels also approaching?c)How can this model give an idea of what happens to the energy levels of an atom or molecule near the ionization threshold?
Physics
1 answer:
natali 33 [55]4 years ago
5 0

Answer:

Answered

Explanation:

Energy of electron in  hydrogen atom is given by

E_n= \frac{13.6}{n^2}

now as becomes large

ΔE= E_n+1 - E_n= 18.6 eV(1/n^2- 1/(n+1)^2)

now, as n increases ΔE_n decreases

in the limit n→∞ ,  ΔE_n→0. Thus with increase in n, energy level come close to each other.

b) Since, the wavelength of the rays depends upon the energy level hence they too come closer.

c)Near the ionization threshold the energy level of the atoms come closer and the total energy of the electron becomes almost so that it can be easily removed from the orbit.

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How can gravitational tugs from orbiting planets affect the motion of a star?.
gayaneshka [121]

Answer:

Gravitational tugs from orbiting planets don't affect the motion of a star. The star, being much larger than the planet, has a much smaller orbit. But it does move slightly. Explain how alien astronomers could deduce the existence of planets in our solar system by observing the Sun's motion.

3 0
2 years ago
A 13.5 μF capacitor is connected to a power supply that keeps a constant potential difference of 24.0 V across the plates. A pie
liubo4ka [24]

Answer:

Explanation:

Capacitance of the capacitor = 13.5μF

Voltage across plate is 24V

Dielectric constant k=3.55.

a. Energy in capacitor is given by

E=1/2CV^2

We want to calculate energy without the dielectric substance

Given that C=13.5 μF and V=24V

The capacitance give is with dielectric so we need to remove it

C=kCo

Co=C/k

Then the Co=13.5μF/3.55

Co=3.803μF

Then

E=(1/2)×3.803×10^-6×24^2

E=1.1×10^-3J

E=1.1mJ

b. Energy in capacitor is given by

E=1/2CV^2

The capacitance given is with a dielectric, so we are going to apply it direct.

Given that C=13.5 μF and V=24V

Then

E=(1/2)×13.5×10^-6×24^2

E=3.89×10^-3J

E=3.9mJ

c. The energy without dielectric is 1.1mJ and the energy with dielectric is 3.9mJ

The energy increase when the dielectric material is added

d. Dielectrics in capacitors serve three purposes: to keep the conducting plates from coming in contact, allowing for smaller plate separations and therefore higher capacitances;

Therefore, Since dielectric allow higher capacitance, and energy of a capacitor is directly proportional to the capacitance, then the higher the capacitance the higher the energy.

6 0
4 years ago
A runner has a temperature of 40°c and is giving off heat at the rate of 50cal/s (a) What is the rate of heat loss in watts? (b)
Andrew [12]

Answer:

(a)  209 Watt

(b) 4482.8 seconds

Explanation:

(a) P = 50×4.18

Where P = rate of heat loss in watt

    P = 209 Watt

Applying,

Q = cm(t₁-t₂)................ Equation 1

Where Q = amount of heat given off, c = specific heat capacity capacity of human, m = mass of the person, t₁ and t₂ = initial and final temperature.

From the question,

Given: m = 90 kg, t₁ = 40°C, t₂ = 37°C

Constant: c = 3470 J/kg.K

Substtut these values into equation 1

Q = 90×3470(40-37)

Q = 936900 J

But,

P = Q/t.............. Equation 2

Where t = time

t = Q/P............ Equation 3

Given: P = 209 Watt, Q = 936900

Substitute into equation 3

t = 936900/209

t = 4482.8 seconds

5 0
3 years ago
Gravity is a force that every mass exerts on every other mass. When you jump up in the air, not only does the Earth exert a grav
sesenic [268]

Answer:

C. Your mass is very small compared to Earth's mass.

Explanation:

Newton's third law of motion states that:

"When an object A exerts a force (action force) on an object B, object B exerts an equal and opposite force (reaction force) on object A".

If we apply this law to the situation described in the problem, we see that:

- The action force is the gravitational force exerted by the Earth on you

- The reaction force is the gravitational force exerted by you on the Earth

And according to the 3rd law, the magnitude of the two forces is equal:

F_1 = F_2 (1)

We also know that, according to Newton's second law of motion, the force on an object is equal to the product between its mass (m) and its acceleration (a):

F=ma

So we can rewrite (1) as

ma = MA

where

m is the your mass

a is your acceleration

M is the Earth's mass

A is the Earth's acceleration

For the term on the left, we see that m is small, so a is larger (therefore, your acceleration is visible). However, for the term on the right, we see that the mass of the Earth is very large (M is very large), therefore, A is very small, which means that the acceleration of the Earth is almost negligible because the Earth's mass is very large.

4 0
4 years ago
At a busy intersection, a 1320-kg car traveling west with a speed of 12 m/s collides head-on with a minivan traveling east with
Elza [17]
p = mv so this question pertains to conservation of momentum.

The momentum of the car is 1320*12 = 15840kgms^-1
For the sake of easiness and the fact negatives are annoying, I will assume east to be positive.

So we know 9.4m - 15840 = (1320+m)*1.5
9.4m - 15840 = 1980+1.5m

Rearranging to solve for m
7.9m = 17820
m = 2255.70 = 2300kg to 2sf

7 0
4 years ago
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