16x-15-9x=13
7x-15=13
+15 +15
x=4
Answer:
C. 8
Step-by-step explanation:
I almost thought this was going to be Pythagorean Theorem, but no.
Use Cosine Law:
cos θ = 
θ = cos−1(0.6)
θ = 53.130...
Now use the SOHCAHTOA ratio for sine (
) to find x now that you have one angle:
sin θ = 
x = 10sinθ (θ isn't needed to be written out as it is shown in the equation above)
x = 8
Answer:Group of answer choices
Step-by-step explanation:
What you first want to do is like and unlike terms so basically liketerms are terms withthe same sign and unlike terms are terms with diferent signs for instinse 3g and 2g are like terms so -33 and -9 and -9 and 9 are unlike terms so you just have to find the like and unlike terms to answer the question!
Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
Suppose f(x) is an even function. The range of g(x) = -3f(2x) is [-9, 3].
Suppose f(x) is an odd function. What is the range of 0.5f(x-3) is [-1.5, 0.5]
