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3 years ago

WILL GIVE BRAINLIEST!!!

Mathematics

1 answer:

Andrews [41]3 years ago

4 0

The 13 stripes alternate red and white: 7 red and 6 white.
Each of 13 stripes is (39 in. / 13) = 3 in. wide.
4 of the 7 red stripes are 39 in. long. The other 3 are 65 in. long.

The total area (l*w) of the flag is (65 in.)*(39 in.)=2535 sq. in.

The red stripes make up an area (l*w) that is:
4*(area of short stripes) + 3*(area of long stripes)
Red area is 4*(39*3) + 3*(65*3) = 1053 sq in.

The fraction of the flag that is red is:
1053 sq. in. / 2535 sq. in.

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Solve 15 – x = 2 a. –13 b. 17 c. 13 d. 3

anyanavicka [17]

The answer should be c. 13

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3 years ago

A motorist travels 122 km before his first stop. If he had 10% of his journey to complete at this point, how long was the total

dimaraw [331]

Answer:

233km

Step-by-step explanation:

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2 years ago

Rodney had 7 toffees MORE than Micah. Micah’s father then gave him 2 more toffees. How many toffees more than Micah would Rodney

WARRIOR [948]

Answer:

Rodney will have 9 toffees more than Micah.

Step-by-step explanation:

Let the numbr of toffee Micah have = x

So, the number of toffee Rodney have = x + 7.

Since, Micah's father gave him 2 more toffees.

Then, number of toffee Micah now have = x + 2

So, number of toffees Rodney will have = (x+7) + 2 = x + 9.

Hence, Rodney will have 9 toffees more than Micah.

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4 years ago

When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let

HACTEHA [7]

Answer:

(a) The value of P (X ≤ 2) is 0.8729.

(b) The value of P (X ≥ 5) is 0.0072.

(d) The probability that none of the 25 boards is defective is 0.2774.

(e) The expected value and standard deviation of X are 1.25 and 1.09 respectively.

Step-by-step explanation:

The random variable X is defined as the number of defective boards.

The probability that a circuit board is defective is, p = 0.05.

The sample of boards selected is of size, n = 25.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={25\choose x}0.05^{x}(1-0.05)^{25-x};\ x=0,1,2,3...$

(a)

Compute the value of P (X ≤ 2) as follows:

P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2)

$P(X\leq =x)=\sum\limits^{2}_{x=0}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=0.2774+0.3650+0.2305\\=0.8729$

Thus, the value of P (X ≤ 2) is 0.8729.

(b)

Compute the value of P (X ≥ 5) as follows:

P (X ≥ 5) = 1 - P (X < 5)

$=1-\sum\limits^{4}_{x=0}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=1-0.9928\\=0.0072$

Thus, the value of P (X ≥ 5) is 0.0072.

(c)

Compute the value of P (1 ≤ X ≤ 4) as follows:

P (1 ≤ X ≤ 4) = P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4)

$=\sum\limits^{4}_{x=1}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=0.3650+0.2305+0.0930+0.0269\\=0.7154$

Thus, the value of P (1 ≤ X ≤ 4) is 0.7154.

(d)

Compute the value of P (X = 0) as follows:

$P(X=0)={25\choose 0}0.05^{0}(1-0.05)^{25-0}=1\times 1\times 0.277389=0.2774$

Thus, the probability that none of the 25 boards is defective is 0.2774.

(e)

Compute the expected value of X as follows:

$E(X)=np=25\times 0.05=1.25$

Compute the standard deviation of X as follows:

$SD(X)=\sqrt{np(1-p)}=\sqrt{25\times 0.05\times (1-0.05)}=1.09$

Thus, the expected value and standard deviation of X are 1.25 and 1.09 respectively.

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4 years ago

Why did they ban squatted trucks??

steposvetlana [31]

Answer:

g o o g l e

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers