Question

1) A football player kicks a ball at an angle of 30 and gives it a velocity of 15m/s.

Answer 1

Answer:

A) 1.53s

B) 19.8m

C) 2.869m

Explanation:

A) The time of flight for a projectile can be calculated using the formula:

t = 2μsinθ/g

Where; u = velocity

θ = angle

g = acceleration due to gravity (9.8m/s^2)

t = 2 × 15 × sin 30°/9.8

t = 30sin30°/9.8

t = 30 × 0.5/9.8

t = 15/9.8

t = 1.53s

B) The horizontal range (distance) for a projectile can be calculated using the formula:

Range = u²sin2θ/ g

Range = 15² sin 2 × 30 / 9.8

Range = 225 sin 60/9.8

Range = 225 × 0.8660/9.8

Range = 194.855/9.8

Range = 19.8m

C) The maximum height for a projectile can be calculated using the formula:

h = u²sin²θ/2g

h = 15² (sin 30)² / 2 × 9.8

h = 225 × 0.25 / 19.6

h = 56.25/19.6

h = 2.869m

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