Answer:
The height from which the egg is dropped is <u>68.54 m</u>.
Explanation:
Given:
Initial velocity of egg is, 
(Dropped means initial velocity is 0)
Time taken is, 
Acceleration experienced by egg is due to gravity, 
The height from which the egg is dropped is, 
Now, we use Newton's equation of motion that relates the distance, initial velocity, time and acceleration.
So, we have the following equation of motion:
Plug in all the given values and solve for 'd'. This gives,
Therefore, the height from which the egg is dropped is 68.54 m.
Answer:
(A) –14m/s
(B) –42.0m
Explanation:
The complete solution can be found in the attachment below.
This involves the knowledge of motion under the action of gravity.
Check below for the full solution to the problem.
List the known information:
Use the kinematic equation 
.
Plug in the given values:
This would be 35.064 m/s downward, or 35 m/s downward with significant figures taken into account.
The answer is 1.99 × 10⁻¹⁰ m.
To calculate this we will use De Broglie wavelength formula:
<span>λ = h/(m*v)
</span><span>λ - the wavelength
</span>h - Plank's constant: h = 6.626 × 10⁻³⁴ Js
v - speed
m - mass
It is given:
<span>λ = ?
</span>m = 9.11 × 10⁻²⁸<span> g
v = </span>3.66 × 10⁶<span> m/s
After replacing in the formula:
</span>λ = h/(m*v) = 6.626 × 10⁻³⁴ /(9.11 × 10⁻²⁸ * 3.66 × 10⁶) = 1.99 × 10⁻¹⁰ m
