All categories

3 years ago

2/3 x (-6/7 + 4/5) = (2/3 x 4/5) x (-6/7) : verify

Mathematics

2 answers:

kifflom [539]3 years ago

5 0

⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✿⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✳︎

Hi my lil bunny!

❀ _____.______❀_______._____ ❀

Let's solve your equation step-by-step.

$(\frac{2}{3}x) ( \frac{-6}{7} + \frac{4}{5}) = [\frac{\frac{2^x4}{3} }{5} ] ( \frac{-6}{7} )$

$\frac{-4}{105} x = \frac{-4x^5}{35}$

Step 1: Subtract $(-4)/35x^5$ from both sides.

$\frac{-4}{105} x - \frac{-4}{35x^5} = \frac{-4x^5}{35} - \frac{-4x^5}{35}\\\\\frac{4}{35}x^5 + \frac{-4}{105} = 0$

Step 2: Factor left side of equation.

$x(0.114286 x^4 - 0.038095 ) = 0$

Step 3: Set factors equal to 0.

$x = 0 or 0.114286 x^4 - 0.038095 = 0\\\\x = 0 or x = -0.759836 or x = 0.759836$

So the answer is : x = 0 or x = - 0.759836 or x = 0.759836

❀ _____.______❀_______._____ ❀

Xoxo, , May

⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✿⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✳︎

Hope this helped you.

Could you maybe give brainliest..?

vlabodo [156]3 years ago

5 0

Answer:

No they can't be equal

Step-by-step explanation:

L.H.S. :-

2/3 × ( -6/7 + 4/5 )

=> 2/3 × -2/35

=> -4/105

R.H.S

(2/3 × 4/5) × -6/7

=> 8/15 × -6/7

=> -48/105

L.H.S IS NOT EQUAL TO R.H.S.

You might be interested in

A baker is calculating the charge for two types of cookies. what formula tells the cost, in dollars, if chocolate chip cookies a

JulsSmile [24]

Answer: Each dozen of chocolate chip cookies costs $1.50/dozen. So if you sell C dozens of them, you win C*$1.50 dollars, where C is a positive integer number. Similar case for the lemon ones, the baker will win L*$1.00 dollars if he sells L dozens of them ( where L is a positive integer), the total charge is the sum of both parts; T = L*$1.00 + C*$1.50.

7 0

3 years ago

Read 2 more answers

How to tell whether its a prime or composite number

Lunna [17]

Prime numbers have only 2 factors 1 and its number for example:
2, 3, 5, 7, 11, 13, 17, 19, 23

Like this 1*2. Or 3*1

Composite numbers have more than two factors for example :
0, 4, 6, 8, 9, 10, 12, 14 15, 16..

For example 0 has many factors
0 times 3 0times 4

8 0

3 years ago

Read 2 more answers

10. Identify the pronoun in this sentence.

brilliants [131]

Answer:

The answer is we. Pronouns are I, you, he/she/it, we, you, they.

4 0

3 years ago

Read 2 more answers

PLEASE HELP FAST <br><br>WILL MARK BRAINLIST

liq [111]

Answer:

1, (c) 2,(c) 3,(a)

Step-by-step explanation:

1, f (x) = 2-x and f(2) = 2-2

for example f(-4) = 2-(-2) = 0

3, 120° - 60° = 60

5 0

2 years ago

Please dont ignore, Need help!!! Use the law of sines/cosines to find..

Ket [755]

Answer:

16. Angle C is approximately 13.0 degrees.

17. The length of segment BC is approximately 45.0.

18. Angle B is approximately 26.0 degrees.

15. The length of segment DF "e" is approximately 12.9.

Step-by-step explanation:

By the law of sine, the sine of interior angles of a triangle are proportional to the length of the side opposite to that angle.

For triangle ABC:

$\sin{A} = \sin{103\textdegree{}}$ ,
The opposite side of angle A $a = BC = 26$ ,
The angle C is to be found, and
The length of the side opposite to angle C $c = AB = 6$ .

$\displaystyle \frac{\sin{C}}{\sin{A}} = \frac{c}{a}$ .

$\displaystyle \sin{C} = \frac{c}{a}\cdot \sin{A} = \frac{6}{26}\times \sin{103\textdegree}$ .

$\displaystyle C = \sin^{-1}{(\sin{C}}) = \sin^{-1}{\left(\frac{c}{a}\cdot \sin{A}\right)} = \sin^{-1}{\left(\frac{6}{26}\times \sin{103\textdegree}}\right)} = 13.0\textdegree{}$ .

Note that the inverse sine function here $\sin^{-1}()$ is also known as arcsin.

By the law of cosine,

$c^{2} = a^{2} + b^{2} - 2\;a\cdot b\cdot \cos{C}$ ,

where

$a$ , $b$ , and $c$ are the lengths of sides of triangle ABC, and
$\cos{C}$ is the cosine of angle C.

For triangle ABC:

$b = 21$ ,
$c = 30$ ,
The length of $a$ (segment BC) is to be found, and
The cosine of angle A is $\cos{123\textdegree}$ .

Therefore, replace C in the equation with A, and the law of cosine will become:

$a^{2} = b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}$ .

$\displaystyle \begin{aligned}a &= \sqrt{b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}}\\&=\sqrt{21^{2} + 30^{2} - 2\times 21\times 30 \times \cos{123\textdegree}}\\&=45.0 \end{aligned}$ .

For triangle ABC:

$a = 14$ ,
$b = 9$ ,
$c = 6$ , and
Angle B is to be found.

Start by finding the cosine of angle B. Apply the law of cosine.

$b^{2} = a^{2} + c^{2} - 2\;a\cdot c\cdot \cos{B}$ .

$\displaystyle \cos{B} = \frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}$ .

$\displaystyle B = \cos^{-1}{\left(\frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}\right)} = \cos^{-1}{\left(\frac{14^{2} + 6^{2} - 9^{2}}{2\times 14\times 6}\right)} = 26.0\textdegree$ .

For triangle DEF:

The length of segment DF is to be found,
The length of segment EF is 9,
The sine of angle E is $\sin{64\textdegree}}$ , and
The sine of angle D is $\sin{39\textdegree}$ .

Apply the law of sine:

$\displaystyle \frac{DF}{EF} = \frac{\sin{E}}{\sin{D}}$

$\displaystyle DF = \frac{\sin{E}}{\sin{D}}\cdot EF = \frac{\sin{64\textdegree}}{39\textdegree} \times 9 = 12.9$ .

7 0

3 years ago