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Hitman42 [59]
2 years ago
6

2/3 x (-6/7 + 4/5) = (2/3 x 4/5) x (-6/7) : verify

Mathematics
2 answers:
kifflom [539]2 years ago
5 0

⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✿⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✳︎

Hi my lil bunny!

❀ _____.______❀_______._____ ❀

Let's solve your equation step-by-step.

(\frac{2}{3}x) ( \frac{-6}{7} + \frac{4}{5}) = [\frac{\frac{2^x4}{3} }{5} ] ( \frac{-6}{7} )

\frac{-4}{105} x = \frac{-4x^5}{35}

Step 1: Subtract (-4)/35x^5 from both sides.

\frac{-4}{105} x - \frac{-4}{35x^5} = \frac{-4x^5}{35} - \frac{-4x^5}{35}\\\\\frac{4}{35}x^5  + \frac{-4}{105} = 0

Step 2: Factor left side of equation.

x(0.114286 x^4 - 0.038095 ) = 0

Step 3: Set factors equal to 0.

x = 0 or 0.114286 x^4 - 0.038095 = 0\\\\x = 0 or x = -0.759836 or x = 0.759836

So the answer is :  x = 0 or x = - 0.759836 or x = 0.759836

❀ _____.______❀_______._____ ❀

Xoxo, , May

⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✿⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✳︎

Hope this helped you.

Could you maybe give brainliest..?

vlabodo [156]2 years ago
5 0

Answer:

No they can't be equal

Step-by-step explanation:

L.H.S. :-

2/3 × ( -6/7 + 4/5 )

=> 2/3 × -2/35

=> -4/105

R.H.S

(2/3 × 4/5) × -6/7

=> 8/15 × -6/7

=> -48/105

L.H.S IS NOT EQUAL TO R.H.S.

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Can someone please help me I really need help help me thank you
harkovskaia [24]

Answer:

<h2><em><u>A to C = 25 </u></em></h2><h2><em><u>A to B = 13 </u></em></h2><h2><em><u>C to B = 37 </u></em></h2><h2><em><u></u></em></h2>

Step-by-Step Explanation:

<em><u>Perimeter</u></em> = 75

<em><u>Sides:</u></em>

2x + 3

3x + 4

2x - 9

<h2 /><h2><em><u>1. Equal the sides added together to the perimeter</u></em></h2>

75 = 2x + 3 + 3x + 4 + 2x - 9

<h2><em><u>2. Simplify Like terms</u></em></h2>

2x + 3 + 3x + 4 + 2x - 9  = 7x - 2

<h2><em><u>3. Place the equation back together</u></em></h2>

75 = 7x - 2

<h2><em><u>4. Isolate the variables and numbers</u></em></h2>

75 = 7x - 2

+2        +2

77 = 7x

<h2><em><u>5. Simplify the equation</u></em></h2>

77 = 7x

/7     /7

<h2><em><u>11 = x </u></em></h2>

<h2><em><u>6. Substitute the value of x into the side lengths.</u></em></h2>

2x + 3 = 2(11) + 3 = 22 + 3 = <em><u>25</u></em>

3x + 4 = 3(11) + 4 = 33 + 4 = <em><u>37</u></em>

2x - 9 = 2(11) - 9 = 22 - 9 = <em><u>13</u></em>

5 0
2 years ago
A cylinder shaped can needs to be constructed to hold 600 cubic centimeters of soup. The material for the sides of the can costs
PSYCHO15rus [73]

Answer:

the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm

Step-by-step explanation:

since the volume of a cylinder is

V= π*R²*L → L =V/ (π*R²)

the cost function is

Cost = cost of side material * side area  + cost of top and bottom material * top and bottom area

C = a* 2*π*R*L + b* 2*π*R²

replacing the value of L

C = a* 2*π*R* V/ (π*R²) + b* 2*π*R²  = a* 2*V/R + b* 2*π*R²

then the optimal radius for minimum cost can be found when the derivative of the cost with respect to the radius equals 0 , then

dC/dR = -2*a*V/R² + 4*π*b*R = 0

4*π*b*R = 2*a*V/R²

R³ = a*V/(2*π*b)

R=  ∛( a*V/(2*π*b))

replacing values

R=  ∛( a*V/(2*π*b)) = ∛(0.03$/cm² * 600 cm³ /(2*π* 0.05$/cm²) )= 3.85 cm

then

L =V/ (π*R²) = 600 cm³/(π*(3.85 cm)²) = 12.88 cm

therefore the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm

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