1 2/6 as an improper fraction
1 answer:
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Answer:
28 units²
Step-by-step explanation:
Assume that your net has the dimensions shown below.
Its area is
2 yellow rectangles = 2(4 × 2) = 2 × 8 = 16 units²
2 grey rectangles = 2(4 × 1) = 2 × 4 = 8 units²
2 green rectangles = 2(2 × 1) = 2 × 2 = <u> 4 units²</u>
TOTAL = 28 units²
The prism's surface area is 28 units².
The probability that an adult likes soccer is aged between 18–30 will be 44.4%.
We have an adult who likes soccer.
We have to determine the probability the adult is aged 18–30.
<h3>What is Probability?</h3>The formula to calculate the probability of occurrence of an event 'A' can be written as -
P(A) =
where -
n(A) = Number of outcomes favorable to event A.
n(S) = Total number of outcomes.
According to question, we have an adult likes soccer.
The answer to this question is based on the hypothesis that the adults between 18 - 30 are highly energetic. To be more precisely - the adults in the range 18 - 24 and 24 - 30 are highly energetic and full of stamina. Above the age 30, the number of adults who like soccer will start to decrease and will hit nearly zero between the age range of 55 - 65 as the adults in this age group found it very difficult to even walk.
Mathematically -
The probability of an event A = an adult likes soccer is aged between 18–30 will be the highest value among the ones mentioned in options.
Hence, the probability that an adult likes soccer is aged between 18–30 will be 44.4%.
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Answer:
The space inside the box = 2197 in³ - 1436.76 in³ is 760.245 in³.
Step-by-step explanation:
Here we have the volume of the cube box given by the following relation;
Volume of cube = Length. L × Breadth, B × Height, h
However, in a cube Length. L = Breadth, B = Height, h
Therefore, volume of cube = L×L×L = 13³ = 2197 in³
Volume of the basketball is given by the volume of a sphere as follows;
Volume =
Where:
r = Radius = Diameter/2 = 14/2 = 7in
∴ Volume of the basketball =
Therefore, the space inside the box that is not taken up by the basketball is found by subtracting the volume of the basketball from the volume of the cube box, thus;
The space inside the box = 2197 in³ - 1436.76 in³ = 760.245 in³.