Answer:
Your answer is 65
Step-by-step explanation:
f(x) = x² - 4x - 12
f(-7) = (-7)² - 4 x (-7) - 12
= 49 - (-28) - 12
= 49 + 28 - 12
= 77 - 12
= <u>65</u>
Answer:
D Numbers that can be written as fractions
Step-by-step explanation:
A <em>rational</em> number is one that can be written as a <em>ratio</em>: a fraction with integer numerator and denominator.
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The term "decimal" as used here is sufficiently non-specific that we cannot seriously consider it to be part of a suitable answer. A terminating or repeating decimal will be a rational number. A non-terminating, non-repeating decimal will not be a rational number.
While integers and whole numbers are included in the set of rational numbers, by themselves, they do not constitute the best description of the set of rational numbers.
Answer:
(i) (f - g)(x) = x² + 2·x + 1
(ii) (f + g)(x) = x² + 4·x + 3
(iii) (f·g)(x) = x³ + 4·x² + 5·x + 2
Step-by-step explanation:
The given functions are;
f(x) = x² + 3·x + 2
g(x) = x + 1
(i) (f - g)(x) = f(x) - g(x)
∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1
(f - g)(x) = x² + 2·x + 1
(ii) (f + g)(x) = f(x) + g(x)
∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3
(f + g)(x) = x² + 4·x + 3
(iii) (f·g)(x) = f(x) × g(x)
∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2
(f·g)(x) = x³ + 4·x² + 5·x + 2
Answer:8sqrt 2 or sqrt 128
Step-by-step explanation:
We can use the Pythagorean Theorem. Since the ladder is leaning against the wall, it is the hypotenuse. It is also 4 feet away from the wall so 12^2-4^2=b^2 b^2=128 so b=8sqrt 2 or sqrt 128.
Answer:
H.A.=4
Step-by-step explanation:
If the bottom equation is factored, you get (x+1)(x-4)
If the V.A. is -1 ( gotten by putting [x+1] equal to zero I'm guessing) then the H.A. can be gotten by putting (x-4) equal to zero.
Also, I graphed it.
