First, determine the molar mass of the empirical formula given for the substance. This can be solved by adding the products of the number of moles and the molar mass of each of the atom as shown below,
M = (3 mols C)(12 g C/1 mol C) + (2 mols H)(1 g H/1 mol H) + (1 mol N)(14 g N/1 mol N)
M = 52 g/mol
Then, divide the given molar mass above by the calculated value.
n = 208.19 g/mol / 52 g/mol = 4
Then, multiply the value of n to the coefficients of the atoms giving us the answer.
<em> ANSWER: C₁₂H₈N₄</em>
We are given an equation 2Mg+O2-> 2MgO and a starting chemical Mg of about 212 g. In order to solve for the amount of O2 needed, we need the molecular weight of Mg and O2.
Molecular weight:
Mg=24.305 g/mol
O2=16(2)=32 g/mol
Note that for every 1 mol of O2, the amount of Mg must be 2 mol.
So,
g O2 = 212 g Mg x1mo Mgl/24.305 g Mg x1mol O2 /2 mol Mg x 32 g O2/mol O2
gO2=139.56 g
Therefore, 139.56 g of O2 is needed for every 212 g Mg.
Answer:
B. two rounds of cell division
Answer:
you can tell diorite is an intrusive igneous rock because it has a coarse-grained texture
Answer:
The answer is 30 g of sodium hydrocarbonate
Explanation:
This is a acid-base reaction, so in order to neutralise the spilled acid, the mol of spilled acid should be calculated.
M = n / V => n = M x V = 0.028 x 6.2 = 0.1736 mol
Since 1 mol of sulfuric acid generates 2 mol of H⁺, so the mole of H⁺ is 0.3472 mol or 0.35 mol with two significant figures.
To neutralized the acid, we need at least the same mole of base, so we need at least 0.35 mol of NaHCO₃, which can be converted to its mass at 29.4 g.
Since the answer need to be expressed in two significant figures and also need to make sure to neutralize all the acid, so we will use a little excess base. The answer is 30 g.
