Answer:
(a) 133.33nm
(b) 600nm
(c) 7,600nm
Explanation:
The concentration of Y can be determined by using the formula:
![Y = \dfrac{[L]}{k_d+[L]}](https://tex.z-dn.net/?f=Y%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7Bk_d%2B%5BL%5D%7D)
where;
[L] = concentration of the binding ligand.
kd = 400 nm
Thus:
When Y = 0.25; we get :
![0.25 = \dfrac{[L]}{400+[L]}](https://tex.z-dn.net/?f=0.25%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7B400%2B%5BL%5D%7D)
0.25 (400 + [L]) = [L]
100 + 0.25[L] = [L]
100 = [L] - 0.25 [L]
100 = 0.75 [L]
[L] = 100/0.75
[L] = 133.33 nm
At, Y = 0.6
![0.6 = \dfrac{[L]}{400+[L]}](https://tex.z-dn.net/?f=0.6%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7B400%2B%5BL%5D%7D)
0.6 (400 + [L]) = [L]
240 + 0.6[L] = [L]
240 = [L] - 0.6 [L]
240 = 0.4 [L]
[L] = 240/0.4
[L] = 600 nm
At, Y = 0.95
![0.95 = \dfrac{[L]}{400+[L]}](https://tex.z-dn.net/?f=0.95%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7B400%2B%5BL%5D%7D)
0.95 (400 + [L]) = [L]
380 + 0.95[L] = [L]
380 = [L] - 0.95 [L]
380 = 0.05 [L]
[L] = 380/0.05
[L] = 7600 nm
Answer:
<h2>
The no. of moles present in one liter solution is 0.843</h2>
Explanation:
Mass of ammonium chloride = 11.5 gm
Molar mass of ammonium chloride = 53.491 gm
No. of moles
N = 0.215 moles
M = 0.843 M
Thus the no. of moles present in one liter solution is 0.843
Answer:
mining of clay limestone and then heated to a certain temperature of 1450⁰ in a cement kiln
Answer : The temperature in degree Celsius is, 
Explanation :
The conversion used for the temperature from Kelvin to degree Celsius is:
where,
= temperature in Kelvin
= temperature in centigrade
As we are given the temperature in Kelvin is, 2.7
Now we have to determine the temperature in Kelvin.
Therefore, the temperature in degree Celsius is,
Answer:
Tincture of iodine, iodine tincture, or weak iodine solution is an antiseptic. It is usually 2–7% elemental iodine, along with potassium iodide or sodium iodide, dissolved in a mixture of ethanol and water. Tincture solutions are characterized by the presence of alcohol.
Explanation:
