Can someone help me with this please??

A car covers a distance of 200 m. If its velocity is 20 m/s, calculate the<br>time taken.

DerKrebs [107]

Answer:

10 seconds

Step-by-step explanation:

Distance = 200 m

Velocity = 20m/s

Time =?

$time = \frac{distance}{velocity} \\ time = \frac{200m}{20m/s} \\ time = 10 \: seconds$

8 0

3 years ago

the monthly budget for the front of the house is $18,000. you spent 9% of the budget on fresh flowers. How much did you spend on

Kipish [7]

To find how much was spent on fresh flowers, we just multiply 9% to the monthly budget, which is $18,000.

To multiply a percent to a number, we must first turn the percent into a decimal. Just divide the percent by 100 to get the decimal form. 9% is 0.09.

$0.09 \times 18000 = 1620$

$1620 was spent on fresh flowers (that's quite a lot of money!)

3 0

3 years ago

10. A car repair company charges a $15 for an

Valentin [98]

$75

If the fixed cost is $15, it can be removed from the two hour charge to give the charge of ONLY two hours, which is $150.

This means the hourly charge is $150÷2, which is $75

8 0

3 years ago

At NC State University, 16.4% of the undergraduate classes have more than 50 students. If a random sample of 200 undergraduate c

Lena [83]

Answer:

We need to check the conditions in order to use the normal approximation.

$np=200*0.164=32.8 \geq 10$

$n(1-p)=200*(1-0.164)=167.2 \geq 10$

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$p =0.164$

And the deviation is given by:

$\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262$

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=200, p=0.164)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We need to check the conditions in order to use the normal approximation.

$np=200*0.164=32.8 \geq 10$

$n(1-p)=200*(1-0.164)=167.2 \geq 10$

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$p =0.164$

And the deviation is given by:

$\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262$

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

6 0

3 years ago

Kevin earned $18 for babysitting 6 hours. Which equation below represents the relationship between dollars earned (d) and hours

Artist 52 [7]

I think it’s number 1

5 0

3 years ago

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