Answer:
Time in which both companies charge same cost = 1.5 hour
Step-by-step explanation:
Given:
Fixed Variable
Premier Landscaping charges $15 $55
Ace Landscaping charges $65
Find:
Time in which both companies charge same cost:
Computation:
Assume in X time both companies charge same cost:
So,
Premier Landscaping total cost = Ace Landscaping total cost
⇒ $15 + $55(Time taken) = $65 (Time taken)
⇒ $15 = $65 (Time taken) - $55(Time taken)
⇒ $15 = $10 (Time taken)
⇒ Time taken = 1.5 hour
Time in which both companies charge same cost = 1.5 hour
Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
= 4i (2i) <span>√6
= 8i^2 </span><span>√6 but i^2 = -1
= - 8</span><span>√6</span><span>
</span>
Answer:
A. change in a dependent variable
