When 280. mL of 1.50 × 10⁻⁴ M hydrochloric acid is added to 135 mL of 1.75 × 10⁻⁴ M Mg(OH)₂, the resulting solution will be?

Chemistry

1 answer:

goldfiish [28.3K]3 years ago

6 0

Answer:

B is the correct answer!

Explanation:

Balanced equation is Mg(OH)2 + 2 HCl = MgCl2 + 2 H2O

HCl is the limiting reactant because it gives the smaller amount of MgCl2 I did the math. This means you will be left with Mg(OH)2 since HCl completely runs out.

If HCl is the limiting reactant, Mg(OH) 2 is the excess reactant.

Mg(OH) 2 is a base, so the solution will be basic.

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Answer:

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Strong acids have a ______ value of Ka and the equlibrium for the reaction with water lies far to the _______.

nika2105 [10]

Answer:

All strong acids have a higher value of $K_{a}$ and the equilibrium for the reaction with water lies far to the right.

Explanation:

All strong acids dissociate completely in the solution. Higher the value of dissociation constant of the acid, higher will be the dissociation of the acid.

The reaction of the acid with water will be favored in the forward direction for acids having higher dissociation constant value ( $K_{a}$ ).

The dissociation of a strong acid say HA in water is shown below $\textrm{HA}\left ( aq \right )+\textrm{H}_{2}\textrm{O}\left ( l \right )\rightleftharpoons \textrm{A}^{-}\left ( aq \right )+\textrm{H}_{3}\textrm{O}^{+}\left ( aq \right )$