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TiliK225 [7]
3 years ago
15

Why are experimental investigations the best type of scientific investigation to demonstrate cause-and-effect relationships? ple

ase help lol
Chemistry
1 answer:
lyudmila [28]3 years ago
7 0

Answer/Explanation:

Experimental investigations are the best type of scientific investigation to demonstrate cause-and-effect relationships because they allow the investigator to actively manipulate variables and control conditions. This change can be measured to gather evidence to support or refute the cause-and-effect relationship. Experimental investigations also use a control group a group that does not receive the factor being tested for comparison.

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Sentence for death rate
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Death rate has been caused by mutliple things in soceity, 254,867 by abortion heart disease 143,385.
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3 years ago
What is the result of adding 2.5 × 10³ and 3.5 × 10²?
Elanso [62]

Answer:

A

Explanation:

It is correct please I hope it helps! :)

7 0
3 years ago
Read 2 more answers
Part a use these data to calculate the heat of hydrogenation of buta-1,3-diene to butane. c4h6(g)+2h2(g)→c4h10(g)
Reptile [31]

<u>Answer:</u> The heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:

\Delta H_{rxn}=\sum [n\times \Delta H_{(product)}]-\sum [n\times \Delta H_{(reactant)}]

For the given chemical reaction:

C_4H_6(g)+2H_2(g)\rightarrow C_4H_{10}(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(1\times \Delta H_{(C_4H_{10})})]-[(1\times \Delta H_{(C_4H_6)})+(2\times \Delta H_{(H_2)})]

We are given:

\Delta H_{(C_4H_{10})}=-2877.6kJ/mol\\\Delta H_{(C_4H_6)}=-2540.2kJ/mol\\\Delta H_{(H_2)}=-285.8kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(1\times (-2877.6))]-[(1\times (-2540.2))+(2\times (-285.8))]\\\\\Delta H_{rxn}=234.2J

Hence, the heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

4 0
3 years ago
Options are upper left upper right bottom left bottom right for both problems please help!
polet [3.4K]

Answer:

(upper right) corner of the periodic table to the bottom left corner

6 0
3 years ago
you are holding a bowling ball with a mass of 6 kg at a height of 1 meter. How much gravitational potential energy does the bowl
Bumek [7]

The formula for GPE is PE=mgh, where “m” is the mass of the object, “g” is the acceleration due to gravity (~9.8 m/s^2 on Earth’s surface), and “h” is the height of the object from the ground. Therefore,

PE=mgh

PE=(6 kg)(9.8 m/s^2)(1 m)

PE=58.8 kg•m^2/s^2 or 58.8 Newtons

The GPE of the bowling ball under these conditions would be about 59 Newtons.

Hope this helps!

7 0
4 years ago
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