If the line BC reflects about a line and point N( 3, 5 ) is the reflection of point B ( 3 , 7 ) then the reflection of C ( 5, 7 ) is O ( 5 , 5 ).
Answer: C ) ( 5, 5 )
Starting from a parent function 
, if you add a constant to the whole function, i.e. you perform the transformation
you shift the graph of the parent function by 
units, upwards if is positive, downwards otherwise.
In this case, so, you're shifting, the graph of 
5 units upwards. Since the parent function passes through the point 
, because 
, the shifted graph mantains the same 
coordinate, but the 
coordinate is increased by 5, because of the 5 units upwards shift.
Answer:
(15°, 165°)
Step-by-step explanation:
Given the equation 6 sin2(x) = 3, we are to find the value of x that satisfies the equation in the interval [0, 2π]
Given
6 sin2(x) = 3,
Divide both sides by 6
6 sin2(x)/6 = 3/6
sin2(x) = 1/2
2x = sin^-1(0.5)
2x = 30°
x = 30°/2
x = 15°
Since sin is positive in the second quadrant, x2 = 180-15
x = 165°
Hence the values within the interval are 15 and 165.
(15°, 165°)
Answer:
w= -5
Step-by-step explanation:
- -2w - 4 + 4 = 6 + 4
- -2w = 10
Isolate "w":
About 1.63 ft.
First subtract 8.5 from 11.75 which is 3.25
then divide 3.25 by 2 which is 1.625
Therefore about 1.63 ft. away from each side.
