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pentagon [3]
3 years ago
11

Which expression is equivalent to V-80? -45 -4.5i 4.5i 4.5

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

-4.5i

Step-by-step explanation:

So if u see v-80, so there is a negative sign alr so u just hv to see

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What is the quotient of 83.3 and 24.5
Svetradugi [14.3K]

Answer:

3.4

Step-by-step explanation:

83.3 divided by 24.5= 3.4

5 0
3 years ago
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Find the missing dimension:if the perimeter is 6yards and the length is 6ft .what is the width?in yards
larisa [96]
Since you haven't identified this figure, I'm going to assume that it's a rectangle.

The Perimeter of a rectangle of length L and width W is P = 2L + 2W.

Here you are given the Perimeter and the length, and are to find the width, W.

Solving the above equation for W, we get P - 2L = 2W.
Dividing by 2 (to isolate that W), we get 

P
-- - L = W
 2

Substitute P= 6 yds and L = 6 feet (or 2 yds), find W (in yards).
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2 years ago
i am doing bad in school i dont understand it i am feeling depressed wish someone would just do my work for me sigh
olga2289 [7]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
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Solve the following equation for the unknown quantity: 12x-8=3x+10. a. x=4 b. =2 c =12 d. x=1/2
dezoksy [38]

Answer:

b. x=2

Step-by-step explanation:

Step 1- Move the variable to one side.

12x-8= 3x+10

-3x     -3x

9x-8= 10

Step 2- Add 8 to both sides.

9x-8= 10

  +8   +8

9x= 18

Step 3- Divide to both sides.

<u>9x</u>= <u>18</u>

9     9

x= 2

5 0
3 years ago
A marine biologist monitors the population of sunfish in a small lake. He records 800 sunfish in his first year, 600 sunfish in
Colt1911 [192]

Answer:

Let's use the variable y to represent the number of years passed since the first year.

The population on the first year (y = 0) was 800

The population in the second year (y = 1) was 600.

The ratio in which the population decreased can be calculated as:

R = 600/800 = 0.75

This means that 600 is the 75% of 800, this also means that between the first year and the second year, the population decreased by the 25%

Now let's look at the ratio between the second and third year (y = 2), the population the third year was 450

Now the ratio is:

R = 450/600 = 0.75

Same as before, then we already can see that the population will decrease by 25% each year.

The generic exponential decay equation is:

f(y) = A*(1  - r)^y

where:

A = initial population, in this case, is 800

y = our variable, in this case, represents the number of years

r = the amount that decreases per each unit of our variable, this must be written in decimal form. In this case, we know that the population decreases by 25% each year, and 25% written in decimal form is 0.25

Also, (1 - r) = R, where R is the ratio we found earlier.

To do this, we just divide 25% by 100% to get (25%/100% = 0.25)

Then our equation will be:

f(y) = 800*(1 - 0.25)^y

f(y) = 800*( 0.75)^y

1) We want to predict when the population will be 200.

to do this, we set:

f(y) = 200 = 800*( 0.75)^y

and solve it for y.

(200/800) = 0.75^y

(1/4) = 0.75^y

Now we can use the relationship:

Ln(a^x) = x*ln(a)

Then let's apply Ln( ) in both sides to get

ln(1/4) = y*ln(0.75)

ln(1/4)/ln(0.75) = y = 4.8 years.

This means that 4.8 years after the first year, the population will be around 200.

2) The population in the 25 th year (this is 24 years after the first one, so we take y = 24) is:

f(24) = 800*(0.75)^(24) = 0.80

Around this point, we will have no more sunfish in the lake.

7 0
3 years ago
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