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Tems11 [23]
3 years ago
9

Without calculating any other co-ordinates, give the x-intercepts (roots), y-intercept, and turning point of the graph y=2x^2-5x

.
Mathematics
1 answer:
klasskru [66]3 years ago
3 0
Y = 2x^2 - 5x
y = x(2x - 5)

x intercepts:-

x(2x - 5) = 0 so these are 0 and 5/2  = 2.5  That is at points (0,0) and (2.5,0)
(Answer)

y-intercept  is when x = 0   so its at 2(x)^2 - 5(0)  = 0 

y intercept at (0,0) Answer

Turning point:-

the x coordinate will be at (2.5 -0 / 2 = 1.25
y coordinate is at  2(1.25^2) - 5*1.25 = -3.125

Turning point is at (11.25,-3.125) Answer
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6 0
2 years ago
2<br> -6x + 5y = 1<br> 6x + 4y = -10
Luba_88 [7]

Answer:

(-1,-1)

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finding y

   -6x + 5y = 1

 + (6x + 4y = -10)

---------------------------

              9y = -9

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finding x

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3 years ago
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Mekhanik [1.2K]

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No

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Hence, no, (-3, 4) doesn't statify the equation y = -2x + 5

6 0
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