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Tems11 [23]
4 years ago
9

Without calculating any other co-ordinates, give the x-intercepts (roots), y-intercept, and turning point of the graph y=2x^2-5x

.
Mathematics
1 answer:
klasskru [66]4 years ago
3 0
Y = 2x^2 - 5x
y = x(2x - 5)

x intercepts:-

x(2x - 5) = 0 so these are 0 and 5/2  = 2.5  That is at points (0,0) and (2.5,0)
(Answer)

y-intercept  is when x = 0   so its at 2(x)^2 - 5(0)  = 0 

y intercept at (0,0) Answer

Turning point:-

the x coordinate will be at (2.5 -0 / 2 = 1.25
y coordinate is at  2(1.25^2) - 5*1.25 = -3.125

Turning point is at (11.25,-3.125) Answer
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Corey gets paid $6 per hour to work at a snack stand. This weekend , he worked on both Saturday and Sunday. he made total of $48
Dahasolnce [82]

Answer:

5 hours

Step-by-step explanation:

1. Find out how many dollars he earned on Saturday

3 x 6 = 18

He earned 18 dollars on Saturday.

2. Subtract 18 from 48 since that is from Saturday, not Sunday

48 - 18 = 30

3. Divide 30 by 6 to see how many hours he worked on Sunday

30/6 = 5

6 0
3 years ago
Which table represents a function?
Oliga [24]

Answer:

table 1

Step-by-step explanation:

table one, because you have different value of x (inputs) with no repetition for the same value

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tekilochka [14]

ratio of 6:10, if you divide both numbers by 2 you get a ratio of 3:5

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4 0
3 years ago
Which of the following is equivalent to sec2θ−1sec2θ for all values of θ for which sec2θ−1sec2θ is defined?
galina1969 [7]

Answer:

2 sin^2 \theta

Step-by-step explanation:

According to the scenario, the following information is given:

= \frac{sec^2 \theta - 1 }{sec^2 \theta}

= (\frac{1}{\frac{cos^2\theta}{\frac{1}{cos^2\theta} }} - 1)

= 1 - cos^2\theta\\\\= 1 - (1 - 2 sin^2 \theta)\\\\= 2 sin^2 \theta

Therefore for the given equation, the answer is 2 sin^2 \theta

5 0
3 years ago
The estimated velocity v (in miles per hour) of a car at the end of a drag race is v=234\sqrt[3]{p/w} , where p is the horsepowe
Dennis_Churaev [7]

Answer:

299 miles per hour

Step-by-step explanation:

v=\frac{234}{\sqrt[3]{\frac{p}{w}}}

v=\frac{234}{\sqrt[3]{\frac{1311}{2744}}}

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Therefore, the velocity of the car at the end of a drag race is 299 miles per hour

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