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Tems11 [23]
4 years ago
9

Without calculating any other co-ordinates, give the x-intercepts (roots), y-intercept, and turning point of the graph y=2x^2-5x

.
Mathematics
1 answer:
klasskru [66]4 years ago
3 0
Y = 2x^2 - 5x
y = x(2x - 5)

x intercepts:-

x(2x - 5) = 0 so these are 0 and 5/2  = 2.5  That is at points (0,0) and (2.5,0)
(Answer)

y-intercept  is when x = 0   so its at 2(x)^2 - 5(0)  = 0 

y intercept at (0,0) Answer

Turning point:-

the x coordinate will be at (2.5 -0 / 2 = 1.25
y coordinate is at  2(1.25^2) - 5*1.25 = -3.125

Turning point is at (11.25,-3.125) Answer
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shutvik [7]
10/(10-6)=10/4.
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Hope this helped :)
7 0
3 years ago
Given that P(E) = 0.38, P(F) = 0.38, and P(E ∩ F) = 0.12. Find P(E ∪ F, how do I work this out?
natulia [17]

Answer: The value of P(E∪F) = 0.64.

Step-by-step explanation:

Since we have given that

P(E) = 0.38

P(F) = 0.38

P(E∩F) = 0.12

So, we need to find the P(E∪F).

As we know the formula for the sets.

P(E\cup F)=P(E)+P(F)-P(E\cap F)\\\\P(E\cup F)=0.38+0.38-0.12=0.64\\\\P(E\cup F)=0.64

Hence,the value of P(E∪F) = 0.64.

3 0
3 years ago
5 times the cube of x divided by 4 times x
arlik [135]

Answer:

5x^2/4

Step-by-step explanation:

5 times the cube of x divided by 4 times x

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3 0
3 years ago
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timama [110]
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Step-by-step explanation:

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3 years ago
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