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Naya [18.7K]
3 years ago
14

How to find only f on a graph that defines a function

Mathematics
1 answer:
puteri [66]3 years ago
3 0

Answer:

Read Below

Step-by-step explanation:

we can represent a function using a graph. Graphs display many input-output pairs in a small space. The visual information they provide often makes relationships easier to understand. We typically construct graphs with the input values along the horizontal axis and the output values along the vertical axis.

The vertical line test can be used to determine whether a graph represents a function. A vertical line includes all points with a particular

x

value. The

y

value of a point where a vertical line intersects a graph represents an output for that input

x

value. If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because that

x

value has more than one output. A function has only one output value for each input value.

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Can someone help me please ?
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Answer:

V= 40.9

Step-by-step explanation:

the top and the bottom side both equal 26.2, if you multiply that number by 2 (Because 2 sides have that same number) you get 52.4. The next step is to take the total perimeter which is 134.2, and subtract 52.4 which brings you to 81.8. Then you divide 81.8 by 2 to get your final answer of 40.9, which is the value of V. Hope this helps!

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2-94. Multiple choice: which of the following numbers could not represent a probability? Write a sentence explaining why they co
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it is A

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X²+y²-6x+14y-1=0<br> and please show your work so I can learn
Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

x^2 + y^2 -6x+14y-1=0

We need to use the Quadratic Formula*

x =\frac{-b+\sqrt{b^2}-4ac }{2a} , \frac{-b-\sqrt{b^2} -4ac }{2a}

Thus, given the problem:

a = 1, b=-6, c=y^2+14y-1

So now we just need to plug them in the Quadratic Formula*

x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2} , x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}

As you can see, it is a mess right now. Therefore, we need to simplify it

x=\frac{6+2\sqrt{10-y^2-14y} }{2}, x = \frac{6-2\sqrt{10-y^2-14y} }{2}

Now that's get us to the final solution:

x=3+\sqrt{10-y^2-14y}, x=3-\sqrt{10-y^2-14y}

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

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