All categories

2 years ago

How to find only f on a graph that defines a function

Mathematics

1 answer:

puteri [66]2 years ago

3 0

Answer:

Read Below

Step-by-step explanation:

we can represent a function using a graph. Graphs display many input-output pairs in a small space. The visual information they provide often makes relationships easier to understand. We typically construct graphs with the input values along the horizontal axis and the output values along the vertical axis.

The vertical line test can be used to determine whether a graph represents a function. A vertical line includes all points with a particular

value. The

value of a point where a vertical line intersects a graph represents an output for that input

value. If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because that

value has more than one output. A function has only one output value for each input value.

You might be interested in

21/5 as a whole number

Softa [21]

4.2 is the answer of this question you are asking ✌️

4 0

2 years ago

Read 2 more answers

Rectangle ABCD was dilated to create rectangle A'B'C'D.

77julia77 [94]

The first thing we must do for this case is to calculate the scale factor.

For this, we make the relationship between two parallel sides.

We have then:

$k =\frac{B'C'}{BC}$

Substituting values we have:

$k = \frac{9.5}{3.8}\\k = 2.5$

We are now looking for the value of AB

We have then:

$AB = \frac{A'B'}{k}$

Substituting values:

$AB = \frac{15}{2.5}\\AB = 6$

Answer:

The scale factor is:

$k = 2.5$

The value of AB is:

$AB = 6$

8 0

3 years ago

Read 2 more answers

To prove that δdef ≅ δdgf by sas, what additional information is needed? ∠def ≅ ∠ dgf ∠dfe ≅ ∠ dfg de ≅ dg dg ≅ gf.

snow_lady [41]

Reflection:

Reflection is a type of rigid transformation which requires the turning of an object, shape or figure about a reference point or line. Therefore, the needed additional information is ∠DFE ≅ ∠ DFG.

Reflection implies turning the given triangle DEF about its side DF, so as to produce an image with the same dimensions but different orientation.

The required proof by Side-Angle-Side (SAS) implies that the relations will be in respect of two of its sides and their included angle.

So According to the above statement,

GF ≅ FE (: given)

DF is the common side to triangles DEF and DFG.

DFG is the included side.

Thus ∠DFE ≅ ∠ DFG (Side-Angle-Side postulate, SAS)

Learn more about Reflection on:

brainly.com/question/26494295

#SPJ4

5 0

1 year ago