The given equality hold true when x = 2.
Put x = 2 in inequality.
2(2) + 3 = 4+3 = 7 = R.H.S.
For x = 4 and 6, L.H.S(2x+3) is greater than 7.
Hence for x = 2, 4 and 6, the above inequality holds true.
Hope this helps!
Answer:
What is the question to this
Step-by-step explanation:
Answer:
Step-by-step explanation:
4a² b³ * (9a⁴b² - 4a² + 3) = 4a²b³ * 9a⁴b² - 4a²b³*4a² + 4a²b³*3
= 36a²⁺⁴ b³⁺² -16a²⁺²b³ + 12a²b³
= 36a⁶b⁵ - 16a⁴b³ + 12a²b³
Answer:
90
Step-by-step explanation:
circumference of total circle = 16 pi
16 pi / 4 pi = 4
1 / 4 =25%
1/4 * 360 = 90
Answer:
This means that for (x-6)(x+3) to be positive, the value of x has to be greater than 6; x>6
Step-by-step explanation:
Step 1
Given the equation;
(x-6)(x+3)
Step 2
To determine the values of x that make the equation positive, the equation can be expressed as;
(x-6)(x+3)>0
x-6>0/(x+3)
x-6>0
x>0+6
x>6
This means that for (x-6)(x+3) to be positive, the value of x has to be greater than 6; x>6
