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gizmo_the_mogwai [7]
3 years ago
8

Consider the regulation of galactose metabolism through GAL4. Which of the following would result from a mutation that allowed G

AL3 to bind to GAL80 in the absence of galactose?
A. There would be no change in the regulation of galactose metabolism because GAL3 normally binds to GAL80 to cause a conformation change in GAL80.
B. GAL80 would no longer be able to stimulate transcription of the genes involved in galactose metabolism.
C. GAL80 would be able to bind to GAL4, and transcription of the genes involved in galactose metabolism would be repressed.
D. Transcription of the genes involved in galactose metabolism would occur both in the presence and in the absence of galactose.
E. GAL4 would no longer be able to bind to the DNA thus, transcription of the genes involved in galactose metabolism would occur.
Biology
1 answer:
evablogger [386]3 years ago
4 0

Answer: Option C.

GAL80 would be able to bind to GAL4, and transcription of the genes involved in galactose metabolism would be repressed.

Explanation:

Gal 3, Gal 80 and Gal 4 are form of proteins which participate in metabolism. They constitute a galactose-responsive switch for the GAL genes When galactose is absent, Gal 80 bind to Gal 4, masking the Gal4AD prevent gene transcription and prevents Gal4-mediated promoter activation

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From a Punnett square you can get the genotypic and phenotypic proportions of the progeny produced from a cross. Cross: PpRr x PpRr. F1: PPRR, PPRr, PPRr, PPrr, PpRr,  Pprr, ppRR,  ppRr, pprr.

<h3>What is a Punnett square?</h3>

The Punnett square is a graphic representation that shows the different types of gamete combinations according to the alleles involved in a cross.

Punnett square shows the probabilities of getting offspring with different genotypes and their consequent phenotypes.

In the exposed example, we know that two genes are involved in the cross.

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Since each genotype in the square results from the combination of parental gametes, we can figure out which are the parental genotypes.

For instance, let us consider the provided genotypes

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We can assume one of the parents provided a P and a R dominant alleles, while the other parent provided another P allele but a r recessive allele.

PR + Pr ⇒ PPRr

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One of the parents provided a p recessive allele and a R dominant allele, The other parent provided another p allele and a r recessive allele.

pR + pr ⇒ ppRr

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Both parents provided p and r recessive alleles.

pr + pr ⇒ pprr

From this information, we can assume parents are heterozygous for both genes.

Cross:

Parentals)        PpRr        x      PpRr

Gametes) PR, Pr, pR, pr     PR, Pr, pR, pr

Punnett square)    PR           Pr          pR         pr

                   PR     PPRR     PPRr      PpRR     PpRr

                   Pr      PPRr      PPrr       PpRr      Pprr

                   pR     PpRR     PpRr      ppRR     ppRr

                   pr      PpRr      Pprr       ppRr      pprr

F1) 1/16 individuals are expected to be PPRR

   2/16 individuals are epected to be PPRr

   1/16 individuals are expected to be PPrr

   2/16 individuals are expected to be PpRR

   4/16 individuals are expected to be PpRr

   2/16 individuals are expected to be Pprr

    1/16 individuals are expected to be ppRR

    2/16 individuals are expected to be ppRr

    1/16 individuals are expected to be pprr

For a better understanding, you will find the Punnett square in the attached files representing the parental gametes with different colors, and the resulting genotypes with a combination of these colors.

In this way, you will notice which gamete comes from which parent.

You can learn more about Punnett squares at

brainly.com/question/25357981

#SPJ1

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