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ss7ja [257]
3 years ago
11

What is the acceleration of a 45 kg mass pushed with 15 N of force? What is the acceleration if the force changes to 25 N? What

if the mass changes to 70 kg?
Physics
2 answers:
Rama09 [41]3 years ago
8 0
F = ma
Rearrange this so acceleration is the subject:
A = f/m

Now input your values into this equation for the first question :
A = f/m
A = 15/45
A = 0.33333333 m/s

Then using this same equation change the force of 15 to 25 :
A = f/m
A = 25/45
A = 0.55555556 m/s

For the last question keep the force of 15N but change the mass to 70kg into the same equation :
A = f/m
A = 15/70
A = 0.21 m/s (rounded)
Contact [7]3 years ago
6 0

Answer:

Part a)

a = \frac{1}{3} m/s^2

Part b)

a = \frac{5}{9} m/s^2

Part c)

a = \frac{3}{14} m/s^2

Explanation:

As per Newton's II law we know that

F = ma

Now we know that

m = 45 kg

F = 15 N

so we will have

15 = 45 a

a = \frac{15}{45} = \frac{1}{3} m/s^2

Now we have

m = 45 kg

F = 25 N

now again from Newton's Law

25 = 45 a

a = \frac{25}{45} m/s^2

a = \frac{5}{9} m/s^2

Now if mass is changed to 70 kg

again we have

15 = 70 a

a = \frac{15}{70}

a = \frac{3}{14} m/s^2

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4 0
3 years ago
A graduate student has done a careful analysis of the spectrum of a star. While she has found lines from many elements, there wa
disa [49]

Explanation:

The lines in the spectra of star is due to absorption of light emitted by star by different elements  present in atmosphere of the star .

If some element is present in the outer atmosphere of he star , it will absorb a particular portion of light , for which there will be black line in the spectrum .

These are called Fraunhoffer's lines .

Now there is no such line at the place of Helium in the light spectrum . This means that Helium element is not present in the outer atmosphere of the star.

7 0
3 years ago
A plane flies at 400 north of East for 150 miles,then flies 200 miles at an angle of 150 west of North. What is the plane's fina
ivanzaharov [21]

Answer:

341.46miles

Explanation:

Find the diagram attachment.

To get the displacement D, we will use the cosine rule as shown;

D² = 200²+150²-2(160)(400)cos65°

D² = 40000+22500-128000cos65°

D² = 62500+54095.14

D² = 116595.14

D = √116595.14

D= 341.46 miles

Hence the plane final displacement is 341.46miles

3 0
2 years ago
Someone is trying to balance a (110cm) plank with certain forces.
Mashutka [201]

Answer:

a. i. 30 Nm ii. This moment is a clockwise positive moment.

b. i. 15 Nm ii, This moment is a counter-clockwise negative moment.

c. i. The plank will not balance. ii. The plank would tip up.

d. 150 N

Explanation:

a) Calculate the moment of the 60N force (about O), then name its type.

i. Calculate the moment of the 60N force (about O)

Since moment = Force × perpendicular distance from point of moment ,

M = Fd

Since F = 60 N and d = 50 cm = 0.5 m

M = 60 N × 0.5 m = 30 Nm

ii. Then name its type.

This moment is a clockwise positive moment.

b) Calculate the moment of the 30N force (about O), then name its type.

i. Calculate the moment of the 30N force (about O),

Since moment = Force × perpendicular distance from point of moment ,

M' = F'd'

Since F' = 30 N and d' = 50 cm = 0.5 m

M' = 30 N × 0.5 m = 15 Nm

ii. Then name its type.

This moment is a counter-clockwise negative moment.

c) Will the plank balance? If not, which way will it tip?

i. Will the plank balance?

The plank will balance if the net moment on it is zero

So net moment, M' = positive moment - negative moment = M - M' = 30 Nm   - 15 Nm = 15 Nm

Since the net moment on the plank is M" = 15 Nm ≠ 0,<u>the plank will not balance.</u>

ii Which way will it tip?

The plank would tip in the direction of the greater moment since the net moment is positive. <u>This moment tilts the plank in a clockwise direction, so the plank would tip up.</u>

d) What extra force would be needed at (B) to balance the plank?

The extra force must balance the net moment,

So M" = F"d" where F" = force and d" = distance of force from O = 10 cm = 0.10 m

F" = M"/d"

= 15 Nm/0.10 m

= 150 N

4 0
3 years ago
What kind of weather would an occuluded front likely bring
abruzzese [7]
An occluded front forms when a cold front catches up with a warm front. So it would bring Sun and warmth.
 
3 0
3 years ago
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