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4 years ago

For an object to be in projectile motion, what force must be acting on it

Physics

1 answer:

Lina20 [59]4 years ago

3 0

Answer:

In projectile motion, only the force of gravity (weight) acts on the object.

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A star rotates in a circular orbit about the center of its galaxy. The radius of the orbit is 6.9 x 1020 m, and the angular spee

andrew-mc [135]

Answer:

2.16 x 10^7 years

Explanation:

R = 6.9 x 10^20 m

ω = 9.2 x 10^-15 rad/s

T = 2π / ω

T = ( 2 x 3.14 ) / ( 9.2 x 10^-15)

T = 6.826 x 10^14 second

T = 2.16 x 10^7 years

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3 years ago

Why are force fields necessary to describe gravity?

artcher [175]

Gravity is a non-contact force.

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4 years ago

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Soil tilth refers to ________. Select one:

Feliz [49]

Answer:

Option c

Explanation:

Soil tilth refers to the physical condition of the soil, particularly with regards to the suitability of the soil for the growth of crop.

The determinants of the tilth in the soil incorporates the arrangement and steadiness of aggregated particles of the soil, pace of water penetration, level of air circulation, dampness content and seepage.

Thus option C follows the definition of the soil tilth.

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4 years ago

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Wrist joint is known gliding joint * 1 point true or False

zepelin [54]

True

Wrist and ankle joints are also known as the gliding joints : )

it's also called the midcarpal joint

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3 years ago

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A 750 g air-track glider attached to a spring with spring constant 14.0 N/m is sitting at rest on a frictionless air track. A 20

alexandr402 [8]

Answer:

the amplitude of the subsequent oscillations is 0.11 m

the period of the subsequent oscillations is 1.94 s

Explanation:

given Information:

the mass of air-track glider, $m_{1}$ = 750 g = 0.75 kg

spring constant, k = 13.0 N/m

the mass of glider, $m_{2}$ = 200 g = 0.2 kg

the speed of glider, $v_{2}$ = 170 cm/s = 1.7 m/s

the amplitude of the subsequent oscillations is A = 0.11 m

according to mechanical enery equation, we have

$A = \sqrt{\frac{m_{1} +m_{2} }{k} }v_{f}$

where

A is the amplitude and $v_{f}$ is the final speed.

to find $v_{f}$ , we can use momentum conservation lwa, where the initial momentum is equal to the final momentum.

$P_{f} = P_{i}$

$(m_{1} +m_{2} )v_{f} = m_{1} v_{1} +m_{2}v_{2}$

$v_{1}$ = 0, thus

(0.75+0.2) $v_{f}$ = (0.75)(0)+(0.2)(1.7)

0.95 $v_{f}$ = 0.34

$v_{f}$ = 0.36 m/s

Now we can calculate the amplitude

$A = \sqrt{\frac{0.75 +0.2 }{10} }0.36$

A = 0.11 m

the period of the subsequent oscillations is T = 1.94 s

the equation for period is

T = 2π $\sqrt{\frac{m_{1}+m_{2} }{k} }$

T = 2π $\sqrt{\frac{0.75+0.2 }{10} }$

T = 1.94 s

7 0

3 years ago