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Minchanka [31]
4 years ago
15

For an object to be in projectile motion, what force must be acting on it

Physics
1 answer:
Lina20 [59]4 years ago
3 0

Answer:

In projectile motion, only the force of gravity (weight) acts on the object.

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An object with an initial speed of 4.0 m/s accelerates uniformly at 2.0 m/s^2
Marta_Voda [28]
An object with an initial speed of 4.0 m/s accelerates uniformly at 2.0 m/s^2
in
5 0
3 years ago
150kg object takes 1.5minutes to travel 2,500 meter straight path it begins the trip traveling 120m/s and decelerates to a veloc
Free_Kalibri [48]
<h2>Answer:</h2>

Acceleration= -1.11 m/sec²


<h2>Explanation:</h2>

Date Given to us is

Mass = 150 kg

Time = 1.5 minutes = 90 seconds

Distance = 2500 meters

Initial Velocity = 120 m/s

Final Velocity = 20 m/s

Acceleration = ?

<u>Solution:</u>

By using First Equation of motion

Vf = Vi + at

Putting the values

20 = 120 + a (90)

Subtracting 120 on both sides

20-120 = 120 + a(90) - 120

-100 = 90 a

Dividing both sides by 90

-100/90 = 90 a / 90

-1.11 = a

So the acceleration is -1.11 m/s²

3 0
4 years ago
A plane flies 600 kilometers away from its bad at 400 meters per second then flies back to its base at 600 meters per second. Wh
tester [92]
Seems to me that it flies 400 m/s there and 600 m/s back the same distance.
therefore the average of 400 and 600 is 500 m/s.  The distance is the same so the normal formula of (d2-d1)/(t2-t1) is applicable.
4 0
4 years ago
Two trains on separate tracks move toward each other. Train 1 has a speed of 125 km/h; train 2, a speed of 94.0 km/h. Train 2 bl
dexar [7]

Answer:

f_{o}=595.98Hz

Explanation:

Given data

Train 1 speed v₀=125 km/h =34.7222 m/s

Train 2 speed vs=94.0 km/h=26.1111 m/s

Speed of sound v=343 m/s

Train 2 frequency fs=500 Hz

To find

Frequency f₀ heard by engineer on train 1

Solution

We can use below formula to find the required frequency

f_{o}=f_{s}(\frac{v+v_{o}}{v-v_{s}} )\\f_{o}=(500Hz)(\frac{343m/s+34.722m/s}{343m/s-26.111m/s} ) \\f_{o}=595.98Hz

4 0
3 years ago
An object moving at a constant speed in a circle is _____.
nordsb [41]

Answer:

A. accelerating

Explanation:

Acceleration is defined as the ratio between the change in velocity and the time taken for the velocity to change:

a=\frac{\Delta v}{\Delta t}

We must note that the velocity is a vector - so it has both a magnitude (the speed) and a direction.

This means that a non-zero acceleration occurs when:

- the speed changes, or

- the direction changes, or

- both the speed and the direction change

For an object moving at constant speed in a circle, the direction changes, so the object is accelerating.

5 0
3 years ago
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