An object with an initial speed of 4.0 m/s accelerates uniformly at 2.0 m/s^2
in
<h2>Answer:</h2>
Acceleration= -1.11 m/sec²
<h2>Explanation:</h2>
Date Given to us is
Mass = 150 kg
Time = 1.5 minutes = 90 seconds
Distance = 2500 meters
Initial Velocity = 120 m/s
Final Velocity = 20 m/s
Acceleration = ?
<u>Solution:</u>
By using First Equation of motion
Vf = Vi + at
Putting the values
20 = 120 + a (90)
Subtracting 120 on both sides
20-120 = 120 + a(90) - 120
-100 = 90 a
Dividing both sides by 90
-100/90 = 90 a / 90
-1.11 = a
So the acceleration is -1.11 m/s²
Seems to me that it flies 400 m/s there and 600 m/s back the same distance.
therefore the average of 400 and 600 is 500 m/s. The distance is the same so the normal formula of (d2-d1)/(t2-t1) is applicable.
Answer:

Explanation:
Given data
Train 1 speed v₀=125 km/h =34.7222 m/s
Train 2 speed vs=94.0 km/h=26.1111 m/s
Speed of sound v=343 m/s
Train 2 frequency fs=500 Hz
To find
Frequency f₀ heard by engineer on train 1
Solution
We can use below formula to find the required frequency

Answer:
A. accelerating
Explanation:
Acceleration is defined as the ratio between the change in velocity and the time taken for the velocity to change:

We must note that the velocity is a vector - so it has both a magnitude (the speed) and a direction.
This means that a non-zero acceleration occurs when:
- the speed changes, or
- the direction changes, or
- both the speed and the direction change
For an object moving at constant speed in a circle, the direction changes, so the object is accelerating.