Answer:
366 m
Explanation:
u = 90 km/h = 25 m/s,
theta = 5 degree
acceleration, a = g Sin theta = 9.8 x Sin 5 = 0.854 m/s^2
The final velocity os zero and let the braking distance be s.
Use third equation of motion
v^2 = u^2 - 2 a s
0 = 25 x 25 - 2 x 0.854 x s
s = 366 m
Answer:
The electric potential at point B is 83.33 V
The magnitude of the electric field at point B is 166.67 N/C
Explanation:
Given;
charge of an object, q = −6.00×10⁻⁹ C
Kinetic energy = 5.00×10⁻⁷ J
Electric potential at point A = +30.0 V
To determine the electric potential at point B, we apply the following formula;
Fd = qEd
Also, Fd is work done in moving the charge to 0.5 m = K.E
Again, Ed is the electric potential at point B (VB)
Substitute for V and K.E in the above equation, we will have;
K.E = q(VB)
VB = K.E/q

To determine the magnitude of the electric field at B, we use equation below;
V = Ed

The efficiency of the wedge is
low because of friction. The amount of work it supplies is small compared to
the amount of work output. The internal resistance of the wedge is incredibly
high due to its heavy weight at the other end of the blade.
final velocity=initial velocity+acceleration*time
i.e V=U+axt
V= 20+6*25
V= 20+150
V= 170
There are 3 feet in a yard.
So, we have to multiply 16*3.
16*3 is 48.
The race is 48 feet long.