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hoa [83]
4 years ago
9

A grocer wants to make a 10-pound mixture of peanuts and cashews that he can sell for $4.75 per pound. If peanuts cost $4.00 per

pound and cashews cost $6.50 per pound, how many pounds of cashews should he use?
a 3
b 4
c 6
d 7
Mathematics
2 answers:
blagie [28]4 years ago
8 0

Answer:

Step-by-step explanation:

4x+(10-x)*6.5 =4.75*10

4x+65-6.5x=47.5

6.5 x-4 x=65-47.5

2.5 x=17.5

x=7

peanuts=7 -pound

cashews=10-7=3 -pound

Aliun [14]4 years ago
6 0

Answer: A grocer wants to make a 10-pound mixture of peanuts and cashews that he can sell for $4.75 per pound. If peanuts cost $4.00 per pound and cashews cost $6.50 per pound, how many pounds of cashews should he use?

a 3

b 4

c 6

d 7

Step-by-step explanation:

3lbs of Cashews

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A city council consists of seven Democrats and five Republicans. If a committee of four people is selected, find the probability
Hoochie [10]

Answer:

The probability  of selecting two Democrats and two Republicans is 0.4242.

Step-by-step explanation:

The information provided is as follows:

  • A city council consists of seven Democrats and five Republicans.
  • A committee of four people is selected.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

{n\choose k}=\frac{n!}{k!\times (n-k)!}

Compute the number of ways to select four people as follows:

{12\choose 4}=\frac{12!}{4!\times (12-4)!}=495

Compute the number of ways to selected two Democrats as follows:

{7\choose 2}=\frac{7!}{2!\times (7-2)!}=21

Compute the number of ways to selected two Republicans as follows:

{5\choose 2}=\frac{5!}{2!\times (5-2)!}=10

Then the probability  of selecting two Democrats and two Republicans as follows:

P(\text{2 Democrats and 2 Republicans})=\frac{21\times 10}{495}=0.4242

Thus, the probability  of selecting two Democrats and two Republicans is 0.4242.

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