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kotegsom [21]
3 years ago
14

which is the false statement about c14? a. it is a stable isotope. b. it is a radioactive isotope. c. it is present in all livin

g things. d. it is used to calculate the age of remains
Chemistry
2 answers:
MariettaO [177]3 years ago
6 0

Answer:

The false statement is option A.

Explanation:

A rare isotope of carbon is carbon-14. The carbon-14 is radioactive and decays to produce nitrogen-14 and an electron. As carbon-14 is radioactive, it decays at a similar rate possessing a half-life of about 5700 years. The isotope is found in all the living things and is generally used to find the age of remains. The process of finding the age of the remains is known as radiocarbon dating. However, the carbon-14 is not a stable component, and this is the reason why it undergoes radioactive decay.

Snowcat [4.5K]3 years ago
3 0
The false is A

as C-14 is an unstable isotope that is radioactive and is present in all living things i can be used to carbon date things 

hope that helps 
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what is the empirical formula of vanadium 1 oxide given that 20.38 grams of vandium combines with oxygen to form 23.58 grams of
Alex

Answer:

The empirical formula is V₂O

Empirical formula of a compound is the formula that shows the simplest whole number ratio of the atoms of elements in a given compound. Empirical formula is normally calculated when the mass of each element in a compound is known or the percentage composition by mass of each element in a compound is known.

Step by Step Explanation:

Step 1: Percentage composition of each element

Percentage composition=(mass of an element/ mass of the compound)100%

Mass of Vanadium = 20.38 g

Mass of the compound = 23.58 g

% composition of Vanadium = (20.38 g/23.58 g) 100%

                                                 = 86.43 %

Mass of Oxygen = 23.58 g -20.38 g

                           = 3.2 g

% composition of oxygen = (3.2/g/23.58 g) 100%

                                          =  13.57%

Step 2: Find the number of atoms of each element in the compound

Number of atoms  = percentage composition/ atomic mass

Atomic mass of Vanadium = 50.94 g/mol

Number of atoms of V = 86.43 /50.94

                                  = 1.6967

Atomic mass of oxygen = 16 g/mol

Number of atoms of O = 13.57/16

                                      = 0.8481

Step 3:  Find the simplest ratio of atoms

Vanadium : Oxygen

            1.6967 : 0.8481

= 1.6967/0.8481 : 0.8481/0.8481

= 2: 1

Whole number ratio = 2 : 1

Therefore; the empirical formula is V₂O

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