1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Allushta [10]
3 years ago
5

PLEASE SOMEBODY HELP PLEASE ! I WILL MARK BRAINLY I PROMISE !

Chemistry
1 answer:
IgorLugansk [536]3 years ago
5 0
A. your reactants are on the left of the arrow.
B. your products are on the left of the arrow.
C.its read as a yeild sign.
D.the s means it's a soild and the g means it's a gas.
You might be interested in
Lion 7
Sidana [21]

Answer:

A.

Explanation:

You should NEVER eat or drink anything in a lab area. You never know what chemicals or gases are in the lab, and they can harm you.

Wearing a drawstring hoodie won't protect you from chemicals.

Don't wait to clean up chemicals, immediately get a teacher and clean it up (follow the teachers instructions). You never know what has spilled, and if it is harmful or not, or if there is a certain procedure to clean it up.

Don't change the equipment in the middle of an experiment. This can tamper with your results, and depending on what you are working with, this can be dangerous.

3 0
2 years ago
Molarity to percent by mass. Convert 1.672 mol/L MgCl2(aq) solution to percent by mass of MgCl2 in the solution. The solution de
nignag [31]

Answer:

\%m/m=14\%

Explanation:

Hello!

In this case, since the molarity of magnesium chloride (molar mass = 95.211 g/mol) is 1.672 mol/L and we know the density of the solution, we can first compute the concentration in g/L as shown below:

[MgCl_2]=1.672\frac{molMgCl_2}{L}*\frac{95.211gMgCl_2}{1molMgCl_2}=159.2\frac{gMgCl_2}{L}

Next, since the density of the solution is 1.137 g/mL, we can compute the concentration in g/g as shown below:

[MgCl_2]=159.2\frac{gMgCl_2}{L}*\frac{1L}{1000mL}*\frac{1mL}{1.137g}=0.14

Which is also the by-mass fraction and in percent it turns out:

\%m/m=0.14*100\%\\\\\%m/m=14\%

Best regards!

6 0
2 years ago
Which of the following is NOT a limiting factor for the number of possible compounds?
babymother [125]

Answer:

all elements have a different atomic number

Explanation:

Atomic number of element does not affect their reactions with others

6 0
3 years ago
Which two elements weather rocks by smoothing them? look below to ansawer
zloy xaker [14]
Water and wind is the correct answer
3 0
2 years ago
Read 2 more answers
Why is MnO2 added to the decomposition of H2O2 reaction?
timofeeve [1]
Answer is: <span>to decrease activation energy.
Manganese(IV) oxide is catalyst in this reaction.
</span>Catalysis <span>is the increase in the </span>rate<span> of a </span>chemical reaction<span> due to the participation of an additional substance called a </span>catalyst. R<span>eactions occur faster with a catalyst because they require less </span>activation energy<span>.</span>
8 0
3 years ago
Read 2 more answers
Other questions:
  • How do you convert 134kj to Calories?
    9·1 answer
  • 25. Why does increasing concentration usually increase reaction rate?
    8·1 answer
  • Fter a radioactive atom decays, it is the same element that it was before with no measurable change in mass. Which kind of decay
    8·2 answers
  • Using the brønsted theory, classify the compounds as either an acid or a base
    13·1 answer
  • An over-the-counter medicated foot powder contains camphor, eucalyptus oil, lemonoil, and zinc oxide. Only one of the ingredient
    5·1 answer
  • The only metal that exists as a liquid at room temperature is
    13·1 answer
  • What is the [H30+] in a solution with (OH) = 1.0 x 10-12 M?
    13·1 answer
  • 1. The definition of the relative atomic mass for an element, X, is:
    8·1 answer
  • Why would Magnesium Phosphate (Mg3(PO4)2) not make an aqueous solution? <br><br> Please help!
    5·2 answers
  • What is the molar mass of K?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!