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Nookie1986 [14]
3 years ago
9

What types of atoms typically form metallic bonds?

Chemistry
1 answer:
beks73 [17]3 years ago
5 0

Answer:

atoms of metallic element.

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How many grams of MgCl2 (molar mass = 95.20 g/mol) will be formed from 25.6 mL of a 0.100 M HCL solution reacting with excess ma
lorasvet [3.4K]
The balanced equation for the above reaction is as follows;
Mg + 2HCl ---> MgCl₂ + H₂
stoichiometry of HCl to MgCl₂ is 2:1
we have been told that Mg is in excess therefore HCl is the limiting reactant 
number of HCl moles reacted - 0.100 mol/L x 0.0256 L = 0.00256 mol
according to molar ratio, number of MgCl₂ moles formed - 0.00256/2 
Therefore number of MgCl₂ moles formed - 0.00128 mol
mass of MgCl formed - 0.00128 mol x 95.20 g/mol = 0.122 g
3 0
2 years ago
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Which of the following is NOT considered a branch of Chemistry?
mestny [16]

Answer:

Pure Chemistry -- is NOT considered a branch of Chemistry.

Explanation:

Second question is number 4.

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3 years ago
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The graphic represents the Milky Way galaxy.
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planets,meteoroids and asteroids  

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2 years ago
Which elements have electron configurations that end in ns 2 np 5 ? halogens noble gases inner transition metals transition meta
4vir4ik [10]
HALOGENS have 7 electrons in their final shell regardless if the total number of atoms.  These 7 electrons would be shared between the 's' and 'p' orbital in the form ns² np⁵ (the same as the question).  Attached is a table that highlights the fact that halogens have the same form in terms of the valence electrons. 

7 0
3 years ago
Write the net ionic equation for the reaction between hydrochloric acid and potassium cyanide. Do not include states such as (aq
zhannawk [14.2K]

Answer: H^++CN^-\rightarrow HCN, product favoured

Explanation:

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we do not include the spectator ions in the equations.

When hydrochloric acid react with potassium cyanide, then it gives potassium chloride and hydrocyanic acid as products.

The complete ionic equation will be:

H^++Cl^-+K^++CN^-\rightarrow K^++Cl^-+HCN

The net ionic equation will not contain spectator ions which are K^+ and Cl^-:

H^++CN^-\rightarrow HCN

The reaction is product favoured.

 

5 0
3 years ago
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