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3 years ago

Determine the pH of a 2.8 ×10−4 M solution of Ca(OH)2.

Chemistry

1 answer:

shepuryov [24]3 years ago

3 0

Answer:

pH = 10.75

Explanation:

To solve this problem, we must find the molarity of [OH⁻]. With the molarity we can find the pOH = -log[OH⁻]

Using the equation:

pH = 14 - pOH

We can find the pH of the solution.

The molarity of Ca(OH)₂ is 2.8x10⁻⁴M, as there are 2 moles of OH⁻ in 1 mole of Ca(OH)₂, the molarity of [OH⁻] is 2*2.8x10⁻⁴M = 5.6x10⁻⁴M

pOH is

pOH = -log 5.6x10⁻⁴M

pOH = 3.25

pH = 14-pOH

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Calculation of ph from hydrogen ion concentration what is the ph of a solution that has an h1 concentration of (a) 1.75 3 1025 m

faltersainse [42]

<h2>Solutions:</h2>

<u>Case a:</u> Finding pH for [H⁺] = 1.75 × 10⁻⁵ mol/L :

As we know pH is given as,

pH = -log [H⁺]

Putting value,

pH = -log [1.75 x 10⁻⁵]

pH = 4.75

<u>Case b:</u> Finding pH for [H⁺] = 6.50 × 10⁻¹⁰ mol/L :

As we know pH is given as,

pH = -log [H⁺]

Putting value,

pH = -log [6.50 × 10⁻¹⁰]

pH = 9.18

<u>Case c:</u> Finding pH for [H⁺] = 1.0 × 10⁻⁴ mol/L :

As we know pH is given as,

pH = -log [H⁺]

Putting value,

pH = -log [1.0 × 10⁻⁴]

pH = 4

<u>Case d:</u> Finding pH for [H⁺] = 1.50 × 10⁻⁵ mol/L :

As we know pH is given as,

pH = -log [H⁺]

Putting value,

pH = -log [1.50 × 10⁻⁵]

pH = 4.82

7 0

3 years ago

¿A qué grupo pertenecen los átomos de Z = 8, Z= 36 y Z=39? ¿Cuántas capas de electrones tiene cada uno? ¿Cuántos electrones harí

zaharov [31]

Answer:

Mira la explicación.

Explanation:

¡Hola!

En este caso, podemos encontrar facilmente el grupo al que pertenecen dichos elementos con números atómicos 8, 36 y 39 respectivamente mediante su búsqueda en la tabla periódica. Así, z=8 corresponde a oxígeno, z=36 a kriptón y z=39 a itrio.

Por otro lado, para saber el número de capas, debemos desarrollar la configuración electrónica para cada uno:

$O: 1s^2,2s^2,2p^4\\Kr: 1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^{10},4p^6\\Y:1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^{10},4p^6,5s^2,4d^1$

Con esto, vemos que oxígeno tiene dos capas, kripton cuatro capas e iritrio cinco, a lo que a oxígeno le faltan dos electrones para llenar dicha capa, a kripton ninguno y a iritrio nueve.

Saludos.

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