Question

A chemist determined by measurements that 0.015 moles of iron participated in a chemical reaction. Calculate the mass of iron that participated in the chemical reaction. Round your answer to 2 significant digits.

Answer 1

Answer: 0.84 g

Explanation:

$\text{ Mass of iron}=\text{ Moles of iron}\times \text{ Molar mass of iron}$

Given: moles of iron = 0.015

Molar mass of iron = 56 g/mol

$\text{ Mass of iron}=0.015\times 56g/mol=0.84g$

Thus 0.84 g of iron participated in the chemical reaction.