Answer: 1:3
Explanation:
1) To state the mole ratio of a product and a reactant we need the chemical equation that shows the reaction.
2) In the case of Fe3O4 and Fe, the chemical equation is:
<span> Fe+H2O → Fe3O4+H2.
3) Now, you balance the equation, which will give you the coefficients of each reactant and product of the chemical reaction:
</span>
<span> 3Fe+4H2O → Fe3O4+4H2
4) From that the mole ratios are:
3 mol Fe : 4 mol 4H2O : 1 mol Fe3O4 : 4 mol H2.
5) The question requires you to find the mole ratio for Fe3O4 to Fe. Tha is:
1 mole Fe3O4 : 3 mole Fe
So, the answer is 1:3
</span>
Weeks = 6 x 4 = 24
Mass leak rate of freon = 41.60 g/week
Mass leak rate of fluorine
Fluorine mass in Freon
= —————————————- X leak rate
M.M. Of Freon
19 x 3
——— X 41.60 = 20.010 gm/week
118.5
Total leaked in 6 months
= 24 x 20.010 = 480.24 gm = 0.480 Kg
The amount left after 20 years = 154.15 mg
<h3>Further explanation
</h3>
The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.
Usually radioactive elements have an unstable atomic nucleus.
The main particles are emitted by radioactive elements so that they generally decay are alpha (α), beta (β) and gamma (γ) particles
The decay formula for isotope :
Then for t=20 years, the amount left :
Since there is no weight, I would assume that this is a 100g of pure compound.
Okay so I would be changing the percentage to gram to solve for the mole.
So
40.0g C (1 mol C/12.01 g C) = 3.33 mol C
6.73g H (1 mol H/1.01 g H ) = 6.66 mol H
53.3g O (1 mol O/16.00 g O) = 3.33 mol O
With that, two of our moles is 3.33, so we consider that are our 1, as it is also the lowest. Therefore the empirical formula is CH2O
Answer:
H₂O + CO₂ → H₂CO₃
Option D is correct.
Law of conservation of mass:
According to this law, mass can neither be created nor destroyed in a chemical equation.
This law was given by French chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.
Now we will apply this law to given chemical equations:
A) H₂ + O₂ → H₂O
There are two H and two O atoms present on left side while on right side only one O and two H atoms are present so mass in not conserved. This option is incorrect.
B) Mg + HCl → H₂ + MgCl₂
In this equation one Mg, one H and one Cl atoms are present on left side of equation while on right side two H, one Mg and two chlorine atoms are present. This equation also not follow the law of conservation of mass.
C) KClO₃ → KCl + O₂
There are one K, one Cl and three O atoms are present on left side of equation while on right side one K one Cl and two oxygen atoms are present. This equation also not following the law of conservation of mass.
D) H₂O + CO₂ → H₂CO₃
There are two hydrogen, one carbon and three oxygen atoms are present on both side of equation thus, mass remain conserved. This option is correct.
