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SpyIntel [72]
1 year ago
15

write the equilibrium expression for the base ionization of the weak base of methylamine, ch3 nh2 . hint: first write the balanc

ed chemical equation for the ionization of ch3 nh2 in water.
Chemistry
1 answer:
svetlana [45]1 year ago
4 0

CH3NH2 + HOH ==> CH3NH3^+ + OH^-Which molecule/ion accepts a proton. That is the base. Which molecule/ion donates a proton. That is the acid.

A stable subatomic particle known by the symbol for "proton"

e elementary charge, p, H+, or 1H+ having a positive electric charge. Its mass is 1,836 times greater than an electron's mass and just a little bit less than that of a neutron (the proton–electron mass ratio). "Nucleons" refers to protons and neutrons together, each of which has a mass of roughly one atomic mass unit (particles present in atomic nuclei).

Each atom. has a nucleus. that contains one or more protons. In order to keep the atomic electrons bound, they offer the central attractive electrostatic force. An element's defining characteristic, known as the atomic number, is the number of protons in the nucleus (represented by the symbol Z)

Learn more about proton here:

brainly.com/question/1252435

#SPJ4

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Chemists investigated an unknown substance and found it to have the following characteristics:
juin [17]

D the substance is a homogeneous mixture

8 0
3 years ago
Tetrachloromethane, CCl4 is produced from the substitution reaction between methane and chlorine gas. If the rate of formation o
Korolek [52]

The rate of disappearance of chlorine gas : 0.2 mol/dm³

<h3>Further explanation</h3>

The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.

For reaction :

\tt aA+bB\rightarrow cC+dD

The rate reaction :

\tt -\dfrac{1}{a}\dfrac{d[-A]}{dt}= -\dfrac{1}{b}\dfrac{d[-B]}{dt}=\dfrac{1}{c}\dfrac{d[C]}{dt}=\dfrac{1}{d}\dfrac{d[D]}{dt}

Reaction for formation CCl₄ :

<em>CH₄+4Cl₂⇒CCl₄+4HCl</em>

<em />

From equation, rate of reaction = rate of formation CCl₄ = 0.05 mol/dm³

Rate of formation of  CCl₄  = reaction rate x coefficient of  CCCl₄

0.05 mol/dm³ = reaction rate x 1⇒reaction rate = 0.05 mol/dm³

The rate of disappearance of chlorine gas (Cl₂) :

Rate of disappearance of  Cl₂  = reaction rate x coefficient of  Cl₂

Rate of disappearance of  Cl₂ = 0.05 x 4 = 0.2 mol/dm³

4 0
3 years ago
How many molecules are there in 840 grams of na2SO4
beks73 [17]

Answer:

3.56x10^24 molecules

Explanation:

The following data were obtained from the question:

Mass of Na2SO4 = 840g

Molar Mass of Na2SO4 = (23 x2) + 32 + (16x4) =46 + 12 + 64 = 142g/mol

From Avogadro's hypothesis, 1mole of any substance contains 6.02x10^23 molecules. This also gives that 1mole of Na2SO4 contains 6.02x10^23 molecules.

If 1 mole (i.e 142g) contains 6.02x10^23 molecules,

Therefore, 840g of Na2SO4 will contain = (840 x 6.02x10^23)/142 = 3.56x10^24 molecules

4 0
3 years ago
Cal is titrating 50.8 mL of 0.319 M HBr with 0.337 M Ba(OH)2. How many mL of Ba(OH)2 does Cal need to add to reach the equivalen
alexgriva [62]

Answer:

V_{base}=24.04mL

Explanation:

Hello!

In this case, according to the chemical reaction by which HBr reacts with Ba(OH)2:

2HBr+Ba(OH)_2\rightarrow BaBr_2+2H_2O

We can see there is a 2:1 mole ratio between the acid and the base; thus, at the equivalent point we can write:

2M_{base}V_{base}=M_{acid}V_{acid}

Therefore, for is to compute the volume of the used base, we proceed as shown below:

V_{base}=\frac{M_{acid}V_{acid}}{2M_{base}}

And we plug in to obtain:

V_{base}=\frac{0.319M*50.8mL}{2*0.337M}\\\\V_{base}=24.04mL

Best regards!

8 0
3 years ago
A 32.78 g sample of a substance is initially at 22.7 °c. after absorbing 2017 j of heat, the temperature of the substance is 173
larisa86 [58]
Heat= mass * change in temperature* specific heat
specific heat=409 J/kg K
3 0
3 years ago
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