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SpyIntel [72]
2 years ago
15

write the equilibrium expression for the base ionization of the weak base of methylamine, ch3 nh2 . hint: first write the balanc

ed chemical equation for the ionization of ch3 nh2 in water.
Chemistry
1 answer:
svetlana [45]2 years ago
4 0

CH3NH2 + HOH ==> CH3NH3^+ + OH^-Which molecule/ion accepts a proton. That is the base. Which molecule/ion donates a proton. That is the acid.

A stable subatomic particle known by the symbol for "proton"

e elementary charge, p, H+, or 1H+ having a positive electric charge. Its mass is 1,836 times greater than an electron's mass and just a little bit less than that of a neutron (the proton–electron mass ratio). "Nucleons" refers to protons and neutrons together, each of which has a mass of roughly one atomic mass unit (particles present in atomic nuclei).

Each atom. has a nucleus. that contains one or more protons. In order to keep the atomic electrons bound, they offer the central attractive electrostatic force. An element's defining characteristic, known as the atomic number, is the number of protons in the nucleus (represented by the symbol Z)

Learn more about proton here:

brainly.com/question/1252435

#SPJ4

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Answer:

Nothing

Explanation:

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3 years ago
A balloon (approximate as a sphere) is inflated such that its
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Answer: 1436 mL

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Compare the sizes and directions of the arrows in each picture representing forces acting on the person. Which of the following
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A, is a girl balancing on her hands, a red arrow is pointing up and is the same length as an arrow pointing down.

Explanation:

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6 0
3 years ago
Write the formula for Zn+2 (SO4)-2
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4 0
3 years ago
In an electrically heated boiler, water is boiled at 140°C by a 90 cm long, 8 mm diameter horizontal heating element immersed in
RideAnS [48]

Explanation:

The given data is as follows.

Volume of water = 0.25 m^{3}

Density of water = 1000 kg/m^{3}

Therefore,  mass of water = Density × Volume

                       = 1000 kg/m^{3} \times 0.25 m^{3}

                       = 250 kg  

Initial Temperature of water (T_{1}) = 20^{o}C

Final temperature of water = 140^{o}C

Heat of vaporization of water (dH_{v}) at 140^{o}C  is 2133 kJ/kg

Specific heat capacity of water = 4.184 kJ/kg/K

As 25% of water got evaporated at its boiling point (140^{o}C) in 60 min.

Therefore, amount of water evaporated = 0.25 × 250 (kg) = 62.5 kg

Heat required to evaporate = Amount of water evapotaed × Heat of vaporization

                           = 62.5 (kg) × 2133 (kJ/kg)

                           = 133.3 \times 10^{3} kJ

All this heat was supplied in 60 min = 60(min)  × 60(sec/min) = 3600 sec

Therefore, heat supplied per unit time = Heat required/time = \frac{133.3 \times 10^{3}kJ}{3600 s} = 37 kJ/s or kW

The power rating of electric heating element is 37 kW.

Hence, heat required to raise the temperature from 20^{o}C to 140^{o}C of 250 kg of water = Mass of water × specific heat capacity × (140 - 20)

                      = 250 (kg) × 40184 (kJ/kg/K) × (140 - 20) (K)

                     = 125520 kJ  

Time required = Heat required / Power rating

                       = \frac{125520}{37}

                       = 3392 sec

Time required to raise the temperature from 20^{o}C to 140^{o}C of 0.25 m^{3} water is calculated as follows.

                    \frac{3392 sec}{60 sec/min}

                     = 56 min

Thus, we can conclude that the time required to raise the temperature is 56 min.

4 0
3 years ago
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