Find the slope of 4x-y=9

30. Felipe va a hacer un banderín para su equipo de fútbol, con las medidas que se indican en la figura. ¿Cuánta tela ocupará pa

blagie [28]

Veremos que el area del banderín es 930cm^2, entonces la opción correcta es A.

<h3>¿Que area tiene el banderin?</h3>

Luego de una pequeña busqueda online, pude ver que el banderin es un triangulo isósceles con base de 31cm y altura de 60 cm.

Recordar que para un triangulo de base b y altura h, el area es:

A = b*h/2

Entonces el area del banderín va a ser:

A = (31cm)*(60cm)/2 = 930cm^2

Entonces la opción correcta es A.

Sí quieres aprender más sobre triangulos, puedes leer:

brainly.com/question/2217700

8 0

2 years ago

Complete the table of ordered pairs for the linear y=2x-8

ExtremeBDS [4]

Given:

Consider the below figure attached with this question.

The linear equation is:

$y=2x-8$

To find:

The values to complete the table of ordered pairs for the given linear equation.

Solution:

We have,

$y=2x-8$

Substituting $x=0$ in the given equation, we get

$y=2(0)-8$

$y=0-8$

$y=-8$

So, the value for first blank is -8.

Substituting $y=-2$ in the given equation, we get

$-2=2x-8$

$-2+8=2x$

$\dfrac{6}{2}=x$

$3=x$

So, the value for second blank is 3.

Substituting $x=2$ in the given equation, we get

$y=2(2)-8$

$y=4-8$

$y=-4$

So, the value for third blank is -4.

Therefore, the required complete table is:

x y

0 -8

3 -2

2 -4

8 0

2 years ago

Find the area of the shaded region of the square to the nearest square inch

sashaice [31]

I need a picture of the problem or something at least

8 0

3 years ago

Which of the equations should anthony pick ?

Komok [63]

Answer:

the third answer

Step-by-step explanation:

hope it helps

7 0

2 years ago

Read 2 more answers

23. A certain type of gasoline is supposed to have a mean octane rating of at least 90. Suppose measurements are taken on of 5 r

Nostrana [21]

Answer:

a) $p_v =P(Z$

b) Since $p_v$ we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

c) $P(\bar X >90)=1-P(Z$

$1-P(Z$

d) For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

$2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}$

And if we solve for n we got:

$n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3$

Step-by-step explanation:

Previous concepts and data given

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We can calculate the sample mean and deviation with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

$\bar X=88.96$ represent the sample mean

$s=1.011$ represent the sample standard deviation

n=5 represent the sample selected

$\alpha$ significance level

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is less than 90, the system of hypothesis would be:

Null hypothesis: $\mu \geq 90$

Alternative hypothesis: $\mu < 90$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{88.96-90}{\frac{0.8}{\sqrt{5}}}=-2.907$

Part a

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=5-1 = 4$

Then since is a left tailed test the p value would be:

$p_v =P(Z$

Part b

Since $p_v$ we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

Part c

We want this probability:

$P(\bar X$

The best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

If we apply this formula to our probability we got this:

$P(\bar X >90)=1-P(Z$

$1-P(Z$

Part d

For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

$2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}$

And if we solve for n we got:

$n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3$

7 0

3 years ago