What is the value of the expression of <br> 3 1/4

James had t toy cars and Paul has 13 more how many cars will James have if Paul gives him half of his cars? ANSWER FAST I WILL G

kogti [31]

Answer:

James will end up with his original t cars and half of (t+13) cars, so will have ...

... t + (t+13/2) = (3t +13)/2 . . . . cars James has after Paul's gift

Step-by-step explanation:

5 0

2 years ago

Is this a discrete or continuous function? Explain.

faust18 [17]

A graph with points (-5, -2), (1, 5), and (-5, 5) represents a discrete function.

<h3>What is a graph?</h3>

A graph can be defined as a type of chart that's commonly used to graphically represent data on both the horizontal and vertical lines of a cartesian coordinate, which are the x-axis and y-axis.

<h3>What is a discrete function?</h3>

A discrete function can be defined as a type of function in which the ordered pair of values on the x-axis and y-axis are separate from each other and unconnected.

In conclusion, the function which this graph represents is a discrete function because both the domain (-5, 1) and range (-2, 5) have discrete set of values, rather than intervals.

Read more on discrete function here: brainly.com/question/25304788

#SPJ1

3 0

1 year ago

A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th

Burka [1]

Answer:

Confidence interval : $21.506$ to $24.493$

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = $\bar{x}=\frac{\sum x}{n}$

Sample mean = $\bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}$

Sample mean = $\bar{x}=23$

Sample standard deviation = $\sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}$

Sample standard deviation = $\sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}$