Question

john and ted have a reputation of being late to events. If john is late 20% of the time and ted is late 40% of the time what is the probability that they will both be on time? Please show your work or explain your answer

Answer 1

Answer:

The probability that they will both be on time is 12/25.

Step-by-step explanation:

John is late 20% of the time.

So, he is prompt 80% of the time.

Ted is late 40% of the time.

So, he is prompt 60% of the time.

Since, both the events are independent,

p(John be on time ∩ Ted be on time) = p(John be on time) × p(Ted be on time)

$= \frac{80}{100}$ × $\frac{60}{100}$

= 0.80 × 0.60

= 0.48 or 48%

$=\frac{12}{25}$

Hence, the probability that they will both be on time is 12/25.