Answer:
The Amount invested at 7% interest is $12,855
The Amount invested at 6% interest = $1,102
Step-by-step explanation:
Given as :
The Total money invested = $13,957
Let The money invested at 7% =
= $A
And The money invested at 6% =
= $13957 - $A
Let The interest earn at 7% = ![I_1](https://tex.z-dn.net/?f=I_1)
And The interest earn at 6% = ![I_2](https://tex.z-dn.net/?f=I_2)
-
= $833.73
Let The time period = 1 year
Now,<u> From Simple Interest method</u>
Simple Interest = ![\dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctextrm%20principal%5Ctimes%20%5Ctextrm%20rate%5Ctimes%20%5Ctextrm%20time%7D%7B100%7D)
Or,
= ![\dfrac{\textrm p_1\times \textrm 7\times \textrm 1}{100}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctextrm%20p_1%5Ctimes%20%5Ctextrm%207%5Ctimes%20%5Ctextrm%201%7D%7B100%7D)
Or,
= ![\dfrac{\textrm A\times \textrm 7\times \textrm 1}{100}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctextrm%20A%5Ctimes%20%5Ctextrm%207%5Ctimes%20%5Ctextrm%201%7D%7B100%7D)
And
= ![\dfrac{\textrm p_2\times \textrm 6\times \textrm 1}{100}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctextrm%20p_2%5Ctimes%20%5Ctextrm%206%5Ctimes%20%5Ctextrm%201%7D%7B100%7D)
Or,
= ![\dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctextrm%20%2813%2C957%20-%20A%29%5Ctimes%20%5Ctextrm%206%5Ctimes%20%5Ctextrm%201%7D%7B100%7D)
∵
-
= $833.73
So,
-
= $833.73
Or, 7 A - 6 (13,957 - A) = $833.73 × 100
Or, 7 A - $83,742 + 6 A = $83373
Or, 13 A = $83373 + $83742
Or, 13 A = $167,115
∴ A = ![\dfrac{167115}{13}](https://tex.z-dn.net/?f=%5Cdfrac%7B167115%7D%7B13%7D)
i.e A = $12,855
So, The Amount invested at 7% interest = A = $12,855
And The Amount invested at 6% interest = ($13,957 - A) = $13,957 - $12,855
I.e The Amount invested at 6% interest = $1,102
Hence,The Amount invested at 7% interest is $12,855
And The Amount invested at 6% interest = $1,102 . Answer