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ivolga24 [154]
3 years ago
7

Please help me on this question I really don't understand it

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
4 0
Itz c the answer is c
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If the measure of angle ACB is 50 degrees, what is the measure of angle AOB
kodGreya [7K]

The answer is 100 degree

8 0
2 years ago
Jenna is drawing a sketch of her room. The room is 15 feet long by 12 feet wide. The
SOVA2 [1]

Answer:

4 inches

Step-by-step explanation:

Actual dimensions:

Length = 15 feet

Width = 12 feet

Scale dimensions:

Length = 5 inches

Width = x inches

Write a proportion:

\dfrac{\text{Actual length}}{\text{Scale length}}=\dfrac{\text{Actual width}}{\text{Scale width}}\\ \\ \\\dfrac{15\ feet}{5\ inches}=\dfrac{12\ feet}{x\ inches}\\ \\x=\dfrac{5\ inches\times 12\ feet}{15\ feet}=4\ inches

3 0
3 years ago
Eric drew a scale drawing of a country park. The scale he used was 1 inch = 2.5 yards. The picnic area is 80 yards wide in real
Alchen [17]
If 1 inch = 2.5 yards then
x inch = 80 yards
cross multiplying we have:
80 × 1 = x × 2.5
x = 80÷ 2.5 = 32 inches
therefore the picnic area is 32 inches in the drawing.
5 0
3 years ago
Solve - 2/5x is less than or equal to 20
sashaice [31]

Answer:

x is less than or equal to 0

Step-by-step explanation:

- you need to multiply both sides of the inequality by 5/2

- then you reduce the numbers with the greatest common factor 5

- then you reduce the numbers with the greatest common factor 2

- any expression multiplied by 0 equals 0

- so you get x is less than or equal to 0

^^^ hope this helps! :)

8 0
3 years ago
Question in image. :)
quester [9]

a. f(a) =5a+12

we have 1. a=6

Therefore, where ever we find a we'll substitute in 6

f(6) =5(6) +12

6f=30+12

6f=42

so therefore 1. a=6 will match c on the right

2. a=2

f(2) =5(2) +12

2f = 10+12

2f = 22

therefore 2. a=2 will match a on the right

3. a=4

f(4) =5(4) +12

4f=20+12

4f=32

therefore 3. a=4 will match d on the right

4. a=5

f(5) =5(5) +12

5f=25+12

5f=37

therefore 4. a=5 will match b on the right

7 0
2 years ago
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