<u>Answer:</u> The unbalanced chemical equations are written below.
<u>Explanation:</u>
An unbalanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is not equal to the total number of individual atoms on the product side. These equations does not follow law of conservation of mass.
The chemical equation for the reaction of nitrogen gas and oxygen gas follows:

The product formed is nitrogen dioxide.
The chemical equation for the decomposition of dinitrogen pentaoxide follows:

The product formed is dinitrogen tetroxide and oxygen gas.
The chemical equation for the reaction of ozone to oxygen gas follows:

The product formed is oxygen gas.
The chemical equation for the reaction of chlorine and sodium iodide follows:

The product formed is sodium chloride and iodine gas
The chemical equation for the reaction of magnesium and oxygen gas follows:

The product formed is magnesium oxide
Answer:
1. 2 M
2. 2 M
Explanation:
1. Determination of the final concentration.
Initial Volume (V₁) = 2 L
Initial concentration (C₁) = 6 M
Final volume (V₂) = 6 L
Final concentration (C₂) =?
The final concentration can be obtained as follow:
C₁V₁ = C₂V₂
6 × 2 = C₂ × 6
12 = C₂ × 6
Divide both side by 6
C₂ = 12 / 6
C₂ = 2 M
Therefore, the final concentration of the solution is 2 M
2. Determination of the final concentration.
Initial Volume (V₁) = 0.5 L
Initial concentration (C₁) = 12 M
Final volume (V₂) = 3 L
Final concentration (C₂) =?
The final concentration can be obtained as follow:
C₁V₁ = C₂V₂
12 × 0.5 = C₂ × 3
6 = C₂ × 3
Divide both side by 3
C₂ = 6 / 3
C₂ = 2 M
Therefore, the final concentration of the solution is 2 M
The answer is Liquid iron.
Answer 2, because when you add salt to something, it cools faster (ex. When you add salt to an ice chest so that it stays cold) and it takes longer to boil (ex. When you boil salt out of ocean water so that its safe to drink) therefore, the more NaCl in the solution, the more it will exibit these properties
Answer:
Moles of
= 6 moles
Explanation:
The reaction of
and
to make
is:
⇒
The above reaction shows that 2 moles of Sc can react with 3 moles of
to form 
Mole Ratio= 2:3
For 10 moles of Sc we need:
Moles of
= 
Moles of
= 
Moles of
=15 moles
So 15 moles of
are required to react with 10 moles of
but we have 9 moles of
, it means
is limiting reactant.


Moles of ScCl_3= 6 moles