A steel cylinder has a pressure of 550 torr at 177 degrees Celsius. What will be the pressure if the temperature is decreased by
1 answer:
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Answer: 8.38 seconds
Explanation:
Integrated rate law for second order kinetics is given by:
= initial concentartion = 0.860 M
a= concentration left after time t = 0.230 M
k = rate constant =
Thus it will take 8.38 seconds for the concentration of A to decrease from 0.860 M to 0.230 M .
Answer:
[S₂] = 1.27×10⁻⁷ M
Explanation:
2 H₂S(g) ⇄ 2 H₂(g) + S₂(g), Kc=1,625x10⁻⁷
The equation of this reaction is:
1,625x10⁻⁷ =
The equilibrium concentrations are:
[H₂S] = 0,162 - 2x
[H₂] = 0,184 + 2x
[S₂] = x
Replacing:
1,625x10⁻⁷ =
Solving:
4x³ + 0,736x² + 0,033856x - 4,3x10⁻⁹
x = 1.27×10⁻⁷
Thus, concentration of S₂ is:
<em>[S₂] = 1.27×10⁻⁷ M</em>