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Nuetrik [128]
3 years ago
13

Which of the following would shift the following equilibrium system to the right? C2H2(g) + H2O(g) ⇌ CH3CHO(g) Removing H2O(g) f

rom the system Adding CH3CHO(g) to the system Removing C2H2(g) from the system Adding H2O(g) to the system
Chemistry
1 answer:
Leni [432]3 years ago
5 0
<h2>Answer:</h2>

<u>The right choice is </u><u>Adding H2O(g) to the system</u>

<h2>Explanation:</h2>

If we dilute a solution by adding solvent like water, all of the concentrations will decrease and a change in Q occurs. If there are more species in solution that are products than reactants then Q will decrease. Hence the reaction will then shift towards the right side which is product side to reach equilibrium because there will be an increase the concentration of the reactants side,

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Which ion would represent the ion of an element from Group 2A?
ziro4ka [17]

Answer:

E²⁺

Explanation:

The group two contain alkaline earth metals.

There are six elements in group 2A.

Beryllium, Magnesium, calcium, strontium, barium and radium.

All members have two valance electrons.

They lose two valance electrons to complete the octet.

When they lose the two valance electrons they form cation X²⁺.

They react with halogens and form salt such as

MgCl₂, CaCl₂ etc.

Mg²⁺  Cl²⁻₂

The oxidation state of halogens are -1, while the elements of group two A shows +2 that's why two atoms of halogen are combine with one atom of alkaline earth metals and make the compound overall neutral.

All the alkaline earth metals have similar properties.

3 0
3 years ago
Which best describes a compound such as sodium chloride?
My name is Ann [436]

Answer:

i think it is the last option a pure substance that can be separated into different elements by chemical means

Explanation:

4 0
3 years ago
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Molodets [167]

Answer:

Here's what I get  

Explanation:

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CH₃C≡CCH₃ —  but-2-yne (PIN); 2-butyne is accepted

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5 0
3 years ago
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How much energy does it take to melt 2 kg of ice? (Refer to table of<br> constants for water.)
ioda
It would be C

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5 0
3 years ago
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2h3po4 + 3mg(oh)2 → mg3(po4)2 + 6h2o phosphoric acid, h3po4, is neutralized by magnesium hydroxide, mg(oh)2, according to the eq
Rina8888 [55]
The balanced equation for the neutralisation reaction is as follows
2H₃PO₄ + 3Mg(OH)₂ --> Mg₃(PO₄)₂ + 6H₂O
stoichiometry of H₃PO₄ to H₂O is 2:6
number of H₃PO₄ moles reacted - 0.24 mol
if 2 mol of H₃PO₄ form 6 mol of H₂O
then 0.24 mol of H₃PO₄ forms - 6/2 x 0.24 = 0.72 mol of H₂O
therefore 0.72 mol of H₂O are formed 
4 0
3 years ago
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