Answers are:
1) The balanced oxidation half reaction: 2I⁻(aq) → I₂(s) + 2e⁻.
Iodine is oxidized (lost electrons) from -1 to neutral charge (0).
2) The balanced reduction half-reaction: 2H₂O(l) + 2e⁻ → H₂(g) + 2OH⁻.
Hydrogen is reduced (gain electrons) from +1 to neutral charge.
3) The oxidation <span>reaction takes place at the anode.</span>
Answer:
Hydrogen concentration = 7.94×10^-3 M
Explanation:
from potenz Hydrogen ( pH ) definition
pH = -log[H+]
2.1 = -log[H+]
2.1/-log = -log[H+]/-log
10^-2.1 = [H+]
[H+] = 7.94×10^-3M
Answer:
B is the answer because it doesn't matches the num of valence electrons
1 Answer. SCooke · Stefan V. 1.2×1023 molecules. Hope this helps
