If the states of matter have changed such as from solid to liquid, you have to remove or add energy.
A physical property does not change the substance.
Solubility would be the answer since all of the rest are changing the substance. They all deal with bonds except solubility.
Answer: D. Solubility
Answer:
-2.86x10³ kJ
Explanation:
The enthalpy of a reaction (ΔH) is defined as the heat produced or consumed by a reaction. In the reaction:
2 C₂H₆(g) + 7 O₂(g) → 4 CO₂(g) + 6 H₂O(g)
The ΔH is the heat envolved in the reaction per 2 moles of C₂H₆. 1.43x10³ kJ are involved when 1 mole reacts. Thus, when 2 moles react, involved heat is:
1.43x10³ kJ ₓ 2 = <em>2.86x10³ kJ</em>. As the reaction is a combustion reaction (Produce CO₂ and H₂O), the heat involved in the reaction is <em>PRODUCED, </em>that means ΔH is negative, <em>-2.86x10³ kJ</em>
Answer: Thus the volume of the balloon at this altitude is 419 L
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 751 mm Hg
= final pressure of gas = 495 mm Hg
= initial volume of gas = 340 L
= final volume of gas = ?
= initial temperature of gas =
= final temperature of gas =
Now put all the given values in the above equation, we get:
Thus the volume of the balloon at this altitude is 419 L
The temperature of the 1 kg water will be lower.
Q=mcΔt
Q1= 1kg*c*Δt(1)
Q2= 2kg*c*Δt(2)
Q1=Q2
1kg*c*Δt(1) = 2kg*c*Δt(2)
Δt(1) = 2Δt(2)
We can see that change in temperature for 1 kg will be 2 times more that change in temperature for 2 kg of water.