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luda_lava [24]
3 years ago
12

What are the lengths of line segments AB and BC?

Mathematics
2 answers:
Natalka [10]3 years ago
7 0

Answer:

AB = 10 and BC = 28

Step-by-step explanation:

The opposite sides of a parallelogram are congruent, thus

AB = DC, that is

3y - 2 = y + 6 ( subtract y from both sides )

2y - 2 = 6 ( add 2 to both sides )

2y = 8 ( divide both sides by 2 )

y = 4

Hence AB = 3y - 2 = (3 × 4) - 2 = 12 - 2 = 10

And

AD = BC, that is

2x - 4 = x + 12 ( subtract x from both sides )

x - 4 = 12 ( add 4 to both sides )

x = 16

Hence BC = x + 12 = 16 + 12 = 28

Gnesinka [82]3 years ago
3 0

Answer:

AB = 10; BC = 28

Step-by-step explanation:

Just took the quiz <3

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Solve completely (all missing sides and all missing angles) using trig ratios or laws. Round to the nearest tenth.
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Answer:

Step-by-step explanation:

3. Use Cosine law to find the  length of the unknown side (PR)

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q² = 33² + 67² -  2* 33*67 Cos 19°

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To find the angle use law of sin

\sf \dfrac{q}{Sin \ Q} =\dfrac{p}{Sin \ P}\\\\\\\dfrac{37.1}{Sin \ 19}=\dfrac{33}{Sin \ P} \\\\\\\dfrac{37.1}{0.33}=\dfrac{33}{Sin \ P}\\\\\\37.1* Sin \ P = 33 *0.33\\\\Sin \ P =\dfrac{33*0.33}{37.1}

Sin P = 0.3

P = Sin^{-1} 0.3\\

P = 17.5°

∠R = 180 - (19 + 17.5)

    = 143.5°

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Step-by-step explanation:

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