A number that is no more than 20

What is the product (<img src="https://tex.z-dn.net/?f=%287%5Csqrt%7B8%7D%20%2B3%5Csqrt%7B12%7D%20%29%287%5Csqrt%7B8%7D%20-3%5Cs

tangare [24]

The product should be 284.

4 0

2 years ago

Which fraction has the value that's equal to 3/4

mamaluj [8]

One of the fractions that’s equal to $\frac{3}{4}$ is $\frac{12}{16}$

<u>Solution:</u>

Given that , we have to find fractions which has the same value as that of the fraction $\frac{3}{4}$

Now, we know that, there are several fractions with values equal to $\frac{3}{4}$

To find them, just multiply the numerator and denominator by the same number.

$\begin{array}{l}{3 \times 2=6} \\\\ {4 \times 2=8}\end{array}$

Therefore, $\frac{6}{8}$ is equal to $\frac{3}{4}$

We can do the same with 4, to get $\frac{12}{16}$ , or any other number beyond that.

Hence, one of the fractions that’s equal to $\frac{3}{4}$ is $\frac{12}{16}$

4 0

3 years ago

How do you evaluate brackets

Arisa [49]

I believe the person meant use pemdas! (order of opporations.)
you know what that is, right ? if you have questions feel free to message me!

8 0

3 years ago

How many square feet of outdoor carpet will need for this hole

Arada [10]

Green area - triangle area = 72-9 = 63 square feet

5 0

3 years ago

Read 2 more answers

In a widget factory, machines A, B, and C manufacture, respectively, 20, 30, and 50 percent of the total. Of their output 6, 3,

steposvetlana [31]

Answer:

38.71% probability it was manufactured by machine A.

29.03% probability it was manufactured by machine B.

32.26% probability it was manufactured by machine C.

Step-by-step explanation:

We have these following probabilities:

A 20% probability that the chip was fabricated by machine A.

A 30% probability that the chip was fabricated by machine B.

A 50% probability that the chip was fabricated by machine C.

A 6% probability that a chip fabricated by machine A was defective.

A 3% probability that a chip fabricated by machine B was defective.

A 2% probability that a chip fabricated by machine C was defective.

The question can be formulated as:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

What are the probabilities that it was manufactured by machines A, B, and C?

Machine A

What is the probability that the widget was manufactures by machine A, given that it is defective?

P(B) is the probability that it was manufactures by machine A. So $P(B) = 0.20$

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine A. So $P(A/B) = 0.06$

P(A) is the probability that a widget is defective. This is the sum of 6% of 20%, 3% of 30% and 2% of 50%. So

$P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031$

So

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.2*0.06}{0.031} = 0.3871$

38.71% probability it was manufactured by machine A.

Machine B

What is the probability that the widget was manufactures by machine B, given that it is defective?

P(B) is the probability that it was manufactures by machine B. So $P(B) = 0.30$

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine B. So $P(A/B) = 0.03$

$P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031$

So

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.3*0.03}{0.031} = 0.2903$

29.03% probability it was manufactured by machine B.

Machine C

What is the probability that the widget was manufactures by machine C, given that it is defective?

P(B) is the probability that it was manufactures by machine C. So $P(B) = 0.50$

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine C. So $P(A/B) = 0.02$

$P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031$

So

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.5*0.02}{0.031} = 0.3226$

32.26% probability it was manufactured by machine C.

6 0

3 years ago