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worty [1.4K]
3 years ago
8

Does anyone know any of them

Mathematics
1 answer:
WINSTONCH [101]3 years ago
5 0

the answer for 53. is the gram.


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HELPP!! PLEASE ITS DUE SOON
Debora [2.8K]

Answer:

100%

Step-by-step explanation:

3 0
3 years ago
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Mutiply 4y-4w^8-3y^5w^3
sukhopar [10]

Answer:

48y⁶w¹¹

Step-by-step explanation:

[-3y⁵][4y] → -12y⁶

×

[w³][-4w⁸] → -4w¹¹

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48y⁶w¹¹

I am joyous to assist you anytime.

8 0
3 years ago
N his road trip, Leon stops to refuel and get some snacks. He has the following purchases:
tresset_1 [31]

Answer:

C. Paid $2.60 too much

Step-by-step explanation:

Gas 12 x 2.89 = 34.68

granola 2 x 1.59 = 3.18 x 1.075 = 3.4185

apple .89 x 1.075 = 0.95675

vitamin water 2 x 1.39 = 2.78 x 1.075 = 2.9885

  34.68
  3.4185
  0.95675
+ 2.9885
---------------------
  $42.04

  $44.64
- $42.04
---------------------
  $2.60

3 0
3 years ago
Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was
andrezito [222]

Answer:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 100, p = 0.42

92% confidence level

So \alpha = 0.08, z is the value of Z that has a pvalue of 1 - \frac{0.08}{2} = 0.96, so Z = 1.75.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.3336

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.5064

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

4 0
3 years ago
Answer this simple quick question!! Pls :)
Alex_Xolod [135]

Answer:

If it is that simple then do it yourself LOL

Step-by-step explanation:

6 0
3 years ago
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