2-5 inches =125miles
4-75inches=237.50 miles.
7.6=380miles
The function shown in the graph is a linear function, for a given linear function, the initial value is obtained at y-intercept. The y-intercept is the point where the graph cuts the y-axis. At this point the value of x is zero. Thus from the graph given, the point x=0 at y=2, hence the initial value is y=2.
Answer: y=2
200 x 4 =. 800 + remainder 3 = to 803 803 divided by 4 = 200.75
For the ODE

multiply both sides by <em>t</em> so that the left side can be condensed into the derivative of a product:


Integrate both sides with respect to <em>t</em> :

Divide both sides by
to solve for <em>y</em> :

Now use the initial condition to solve for <em>C</em> :



So the particular solution to the IVP is

or
