Depends on where you live but generally speaking it is either June or July
Answer:
0.0010 w/v %
Explanation:
Based on the reaction:
NiCl₂(aq) + 2AgNO₃(aq) → 2AgCl(s) + Ni(NO₃)₂(aq)
Finding the moles of AgCl produced we can find the moles of NiCl in the reaction medium and its mass:
<em>Moles AgCl -Molar mass: 143.32g/mol-:</em>
5.8mg = 5.8x10⁻³g * (1mol / 143.32g) = 4.047x10⁻⁵ moles AgCl
<em>Moles NiCl₂:</em>
4.047x10⁻⁵ moles AgCl * (1mol NiCl₂ / 2mol AgCl) = 2.023x10⁻⁵ moles NiCl₂
<em>Mass NiCl₂ -Molar mass: 129.60g/mol-:</em>
2.023x10⁻⁵ moles NiCl₂ * (129.60g / mol) = 2.62x10⁻³g of NiCl₂ are produced.
And the concentration in w/v% is:
2.62x10⁻³g NiCl₂ / 250mL * 100 =
<h3>0.0010 w/v %</h3>
Answer:
Explanation:
Hello there!
In this case, since the density of the metal is computed as shown below:
We need to calculate the volume of the solid by subtracting the final volume and the initial volume of water:
Thus, we obtain:
Best regards!
Answer:
A
Explanation:
it becomes a positive charge and fully filled