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daser333 [38]
2 years ago
8

. Which of the following statements about noble gases is NOT true?

Chemistry
2 answers:
WARRIOR [948]2 years ago
7 0

Answer:

d, All of them are found in Earth's atmosphere in small amounts

weqwewe [10]2 years ago
7 0
The answer is C, because they have no desire to react according to their complete set of electrons.
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Idenify each statement below as either oxidation or reduction.
Alenkasestr [34]

Answer:

1 = oxidation

2 = reduction

Explanation:

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

2I- ----> I₂+ 2e⁻

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

F + e⁻ ----> F⁻

Consider the following reactions.

4KI + 2CuCl₂  →   2CuI  + I₂  + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced.

CO + H₂O   →  CO₂ + H₂

the oxidation state of carbon is +2 on reactant  side and on product side it becomes  +4 so carbon get oxidized.

Na₂CO₃ + H₃PO₄  →  Na₂HPO₄ + CO₂ + H₂O

The oxidation state of carbon on reactant side is +4. while on product side is  also +4 so it neither oxidized nor reduced.

H₂S + 2NaOH → Na₂S + 2H₂O

The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.

4 0
2 years ago
What is an element that has more valence electrons than fluorine and less energy levels than sodium?
Radda [10]
From the periodic chart the only element between F and Na is Neon. Neon has one more valence electron 8 than fluorine 7, and is one energy level shy of Na.<span>
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5 0
2 years ago
A tanker truck carrying 6.05×103 kg of concentrated sulfuric acid solution tips over and spills its load. The sulfuric acid solu
irinina [24]

Answer:

6,216.684 kilograms of sodium carbonate must be added to neutralize 6.05\times 10^3 kg of sulfuric acid solution.

Explanation:

Mass of sulfuric acid solution = 6.05\times 10^3 kg=6.05\times 10^6 g

1 kg = 10^3 g

Percentage mass of sulfuric acid = 95.0%

Mass of sulfuric acid = \frac{95.0}{100}\times 6.05\times 10^6 g

=5,747,500 g

Moles of sulfuric acid = \frac{5,747,500 g}{98 g/mol}=58,647.96 mol

H_2SO_4+Na_2CO_3\rightarrow Na_2SO_4+CO_2+H_2O

According to reaction , 1 mole of sulfuric acid is neutralized by 1 mole of sodium carbonate.

Then 58,647.96 moles of sulfuric acisd will be neutralized by :

\frac{1}{1}\times 58,647.96 mol=58,647.96 mol of sodium carbonate

Mass of 58,647.96 moles of sodium carbonate :

106 g/mol\times 58,647.96 mol=6,216,683.76 g

6,216,683.76 g = 6,216,683.76 × 0.001 kg = 6,216.684 kg

6,216.684 kilograms of sodium carbonate must be added to neutralize 6.05\times 10^3 kg of sulfuric acid solution.

3 0
3 years ago
If an atom of thorium-234 were to undergo beta emission twice, which atom would result?
AnnZ [28]

Answer:

The answer to your question is  U-234

Explanation:

Data

Thorium-234

beta emission twice

Definition

Beta emission is when a beta particle (electron) is emitted from an atomic nucleus.

First beta emission

                                            ²³⁴₉₀Th   ⇒    ²³⁴₉₁Pa + e⁻

Second beta emission

                                            ²³⁴₉₁ Pa   ⇒  ²³⁴₉₂U  + e⁻

The atom will be Uranium-324

6 0
3 years ago
Read 2 more answers
What is the formula used to determine the % yield?
Illusion [34]
You multiply the percentage and theoretical yield together.
8 0
2 years ago
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