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2 years ago

. Which of the following statements about noble gases is NOT true?

Chemistry

2 answers:

WARRIOR [948]2 years ago

7 0

Answer:

d, All of them are found in Earth's atmosphere in small amounts

weqwewe [10]2 years ago

7 0

The answer is C, because they have no desire to react according to their complete set of electrons.

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True or False? In a C++ floating-point constant, a decimal point is not required if exponential (E) notation is used.

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Answer:

The answer is True

Explanation:

This is because they are equivalent and have same number of bit.

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2 years ago

is it true that in a solution the tiny pieces of one substance are spread equally through the other substance

ziro4ka [17]

Yes this is true otherwise it would not be a solution

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2 years ago

In this experiment, you were asked to calculate your percent yield of alum assuming that you started with pure aluminum. Actuall

neonofarm [45]

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Explanation:

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3 years ago

Polonium has a mass number of 212 and an atomic number of 84. In a balanced nuclear reaction, polonium releases an alpha particl

antoniya [11.8K]

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2 years ago

A mouse is placed in a sealed chamber with air at 769.0 torr. This chamber is equipped with enough solid KOH to absorb any CO2 a

svlad2 [7]

<u>Answer:</u> The amount of oxygen gas consumed by mouse is 0.202 grams.

<u>Explanation:</u>

We are given:

Initial pressure of air = 769.0 torr

Final pressure of air = 717.1 torr

Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr

To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 51.9 torr

V = Volume of the gas = 2.20 L

T = Temperature of the gas = 292 K

R = Gas constant = $62.364\text{ L. Torr }mol^{-1}K^{-1}$

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

$51.9torr\times 2.20L=n\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 292K\\\\n=\frac{51.9\times 2.20}{62.364\times 292}=0.0063mol$

To calculate the mass from given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of oxygen gas = 0.0063 moles

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

$0.0063mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0063mol\times 32g/mol)=0.202g$

Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.

5 0

2 years ago