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kifflom [539]
3 years ago
5

What 1.62 divided 18564/

Mathematics
1 answer:
Vika [28.1K]3 years ago
8 0
<span>The answer should be 0.00008726567

Hope this helps! </span>
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Brooklyn is going to invest in an account paying an interest rate of 1.9% compounded continuously. How much would Brooklyn need
shusha [124]
Bruh this is it this is it
5 0
3 years ago
Read 2 more answers
jasmine is 23 years old. jasmine is 3 tears less than half of george’s age. write and solve an equation to find george’s age
Sholpan [36]
George(g) is 40 years old.

8 0
2 years ago
Please help please i need help
PtichkaEL [24]

Answer: the second option is the correct answer.

Step-by-step explanation:

In an arithmetic sequence, the consecutive terms differ by a common difference.

The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + d(n - 1)

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = 6

d = 17

n = 18

We want to determine the value of the 18th term, T18. Therefore,

T18 = 6 + 17(18 - 1)

T18 = 6 + 17 × 17

T18 = 6 + 289

T18 = 295

7 0
2 years ago
The graph of y=tan(x) is vertically stretched by a factor of 2, shifted a distance of 1 units to the left, and then translated 7
Klio2033 [76]

<u>Answer:</u>

Equation for the curve in its final position is y = 2tan( x + 1 ) + 7.

<u>Step-by-step explanation:</u>

We have to find equation for the curve of y=tan(x) ,with following transformations:

<em>vertically stretched by a factor of 2:</em>  y = 2tan(x)

<em>shifted a distance of 1 units to the left:</em> y = 2tan( x+1 )

<em>translated 7 units upward:</em> y = 2tan( x + 1 ) + 7

3 0
3 years ago
A. For exercises 1 and 2, a set of data has a normal distribution with a mean of 120 and a standard deviation of 10.
Molodets [167]
A1.) <span>the interval about the mean within which 90% of the data lie = 120 + or - 1.645(10) = 120 + or - 16.45 = 120 - 16.45 to 120 + 16.45 = 103.55 to 136.45

2.) P(100 < X < 140) = P(X < 140) - P(X < 100) = P(z < (140 - 120)/10) - P(z < (100 - 120)/10) = P(z < 2) - P(z < -2) = P(z < 2) - [1 - P(z < 2)] = 2P(z < 2) - 1 = 2(0.97725) - 1 = 1.9545 - 1 = 0.9545 = 95.5%

B1.) </span><span>the interval about the sample mean that has a 1% level of confidence is 500 + or - 2.575(80/√1000) = 500 + or - 7 = 500 - 7 to 500 + 7 = 493 to 507

2.) 2P(z < a) - 1 = 0.90
2P(z < a) = 1.90
P(z < a) = 0.95
a = 1.645
(b - 500)/(80/√1000) = 1.645
b - 500 = 4
b = 500 + 4 = 504
The </span><span>interval about the sample mean such that the probability is 0.90 that the mean number lies within the interval is 496 - 504.</span><span />
4 0
3 years ago
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